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3 years ago

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In July 2019, there were 1.5 million people who were marginally attached to the labor force, essentially unchanged from a year e

arlier. These are people who were not in the labor force, although they wanted work and were available for it and had looked for jobs at some point in the previous 12 months. They were not counted as unemployed because they had not actively searched for work in the 4 weeks preceding the survey.

1 answer:

dybincka [34]3 years ago

5 0

Answer:

D. The large number of marginally attached and discouraged workers shows the failure to paint a true picture of unemployment in this country.

Step-by-step explanation:

You might be interested in

Which graph shows a function with a zero of –5?

Vedmedyk [2.9K]

Answer:

Look for the y-intercept where the graph crosses the y-axis. Look for the x-intercept where the graph crosses the x-axis. Look for the zeros of the linear function where the y-value is zero.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Two ships set sail in different directions from the same place. Tyler's ship sail 35 miles while Noah's ship sails for 42 miles.

earnstyle [38]

Answer:

<em>The angle between their paths when they started is 93°.</em>

Step-by-step explanation:

<u>The Law of Cosines</u>

It relates the length of the sides of a triangle with one of its internal angles.

Let a,b, and c be the length of the sides of a given triangle, and x the included angle between sides a and b, then the following relation applies:

$c^2=a^2+b^2-2ab\cos x$

When the two ships travel in different directions from the same point in the plane, they form an angle we called x in the image below.

Tyler's ship sails a=35 miles and Noah's ship sails for b=42 miles. At some time they are c=56 miles apart.

Since we know the values of all three side lengths, we solve the equation for x:

$\displaystyle \cos x=\frac{a^2+b^2-c^2}{2ab}$

Substituting values:

$\displaystyle \cos x=\frac{35^2+42^2-56^2}{2(35)(42)}$

Calculating:

$\displaystyle \cos x=-\frac{147}{2940}=-\frac{1}{20}$

Computing the inverse cosine:

$x = \arccos(-0.05)$

$x \approx 93^\circ$

The angle between their paths when they started is 93°.

6 0

3 years ago

Mr. Nelson drove for 6 2/3 hours at an average of 57 mph. How far did he drive?

xxMikexx [17]

$6\dfrac{2}{3}=\dfrac{6\cdot3+2}{3}=\dfrac{20}{3}\\\\v=\dfrac{s}{t}\\\\v=57mph;\ t=\dfrac{20}{3}h;\ s=?$

substitute

$\dfrac{s}{\frac{20}{3}}=57\ \ \ |\cdot\dfrac{20}{3}\\\\s=57\cdot\dfrac{20}{3}\\\\s=19\cdot20\\\\s=380\ miles$

Answer: 380miles.

6 0

3 years ago

Solve the simultaneous equations<br> 3<br> 2x - y = 7<br> xy = 15

ehidna [41]

Answer:

(5, 3 ) and (- $\frac{3}{2}$ , - 10 )

Step-by-step explanation:

Given the 2 equations

2x - y = 7 → (1)

xy = 15 → (2)

Rearrange (1) expressing y in terms of x , that is

y = 2x - 7 → (3)

Substitute y = 2x - 7 into (2)

x(2x - 7) = 15

2x² - 7x = 15 ( subtract 15 from both sides )

2x² - 7x - 15 = 0 ← in standard form

(x - 5)(2x + 3) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 5 = 0 ⇒ x = 5

2x + 3 = 0 ⇒ 2x = - 3 ⇒ x = - $\frac{3}{2}$

Substitute these values into (3) for corresponding values of y

x = 5 : y = 2(5) - 7 = 10 - 7 = 3 ⇒ (5, 3 )

x = - $\frac{3}{2}$ : y = 2(- $\frac{3}{2}$ ) - 7 = - 3 - 7 = - 10 ⇒ (- $\frac{3}{2}$ , - 10 )

8 0

3 years ago

If mSW = (12x-5)°, mTV= (2x+7)°,and m angle TUV = (6x-19)°, find mSW

svet-max [94.6K]

Given:

Consider the below figure attached with this question.

m(arc(SW)) = (12x-5)°, m(arc(TV))= (2x+7)°,and measure of angle TUV = (6x-19)°.

To find:

The m(arc SW).

Solution:

Intersecting secant theorem: If two secants intersect outside the circle, then the angle on the intersection is half of the difference of the larger subtended arc and smaller subtended arc.

Using Intersecting secant theorem, we get

$m\angle TUV=\dfrac{1}{2}(m(arc(SW))-m(arc(TV)))$

$6x-19=\dfrac{1}{2}((12x-5)-(2x+7))$

$6x-19=\dfrac{1}{2}(12x-5-2x-7)$

$6x-19=\dfrac{1}{2}(10x-12)$

Multiply both sides by 2.

$2(6x-19)=10x-12$

$12x-38=10x-12$

$12x-10x=38-12$

$2x=26$

Divide both sides by 2.

$x=13$

Now, the measure of arc SW is:

$m(arc(SW))=(12x-5)^\circ$

$m(arc(SW))=(12(13)-5)^\circ$

$m(arc(SW))=(156-5)^\circ$

$m(arc(SW))=151^\circ$

Therefore, the measure of arc SW is 151 degrees.

7 0

3 years ago