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3 years ago

How many lines of symmetry does this shape have

Mathematics

1 answer:

TEA [102]3 years ago

5 0

Answer:

Step-by-step explanation:

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Anyone knows the answer

vesna_86 [32]

Answer:

it might be 390

Step-by-step explanation:

hope this helps

7 0

2 years ago

Use the diagram to complete the statement.

Dima020 [189]

Answer:

∠FJH ≅ ∠BJA

Step-by-step explanation:

From the image we can see that the only congruent relation ∠FJH has is with ∠BJA which is due to these angles being vertically opposite

So, ∠FJH and ∠BJA are vertically opposite and hence, congruent. We can say that ∠FJH ≅ ∠BJA

4 0

3 years ago

Find a quadratic polynomial with integer coefficients which has x = 2/9, ± SQRT23/9 as its real zeros.

melomori [17]

Answer:

The quadratic polynomial with integer coefficients is $y = 81\cdot x^{2}-36\cdot x -19$ .

Step-by-step explanation:

Statement is incorrectly written. Correct form is described below:

Find a quadratic polynomial with integer coefficients which has the following real zeros: $x = \frac{2}{9}\pm \frac{\sqrt{23}}{9}$ .

Let be $r_{1} = \frac{2}{9}+\frac{\sqrt{23}}{9}$ and $r_{2} = \frac{2}{9}-\frac{\sqrt{23}}{9}$ roots of the quadratic function. By Algebra we know that:

$y = (x-r_{1})\cdot (x-r_{2}) = x^{2}-(r_{1}+r_{2})\cdot x +r_{1}\cdot r_{2}$ (1)

Then, the quadratic polynomial is:

$y = x^{2}-\frac{4}{9}\cdot x -\frac{19}{81}$

$y = 81\cdot x^{2}-36\cdot x -19$

The quadratic polynomial with integer coefficients is $y = 81\cdot x^{2}-36\cdot x -19$ .

5 0

3 years ago

-7,5 + 4,2 =? -0,9 * 2,7 =?

Gekata [30.6K]

Answer:

-7.5+4.2=-3.3

-0.9*2.7=-2.43

7 0

2 years ago

Which anwser is equal to i^39?

sleet_krkn [62]

Answer:

Step-by-step explanation:

7 0

3 years ago