The values of a, b, and c are -4,0 and 0 and the parabola opens downward with y-intercept (0,0).
we have
y=-4x^2
<h3>What is the standard form of the quadratic equation?</h3>
The quadratic equation in standard form is equal to
ax^2+bx+c=0
So,In this problem
a=-4, b=0 and c=0
The y-intercept is the value of y when the value of x is equal to zero
y=-4(0)^2=0
The y-intercept is the point (0,0)
The coefficient a is negative, therefore the parabola opens down.
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Uhh I think something like y=x+5
Answer: 4n or 4 x n or 4 * n
Step-by-step explanation:
Outliers should be excluded when producing a trend line, regardless of the method used.
The student got a score of 100 with no sleep.
This data pair was a rare event.
If the outlier was included, it would cause the trend line to misrepresent the typical data relationship.
42 is the right answer that your looking for your welcome
