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2 years ago

Are these figures below similar? NO LINKS!! NEED ANSWER ASAP

Mathematics

2 answers:

jasenka [17]2 years ago

7 0

Yes they are hope it helps.

Vinvika [58]2 years ago

6 0

Yes they are
Hope this helps

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Convert the following equation into slope-intercept form. x - 26y = 52

Softa [21]

The equation in slope intercept form would be: y= 1/26x - 2

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3 years ago

Read 2 more answers

HELP! Find the value of sin 0 if tan 0 = 4; 180 < 0< 270

BabaBlast [244]

Hi there! Use the following identities below to help with your problem.

$\large \boxed{sin \theta = tan \theta cos \theta} \\ \large \boxed{tan^{2} \theta + 1 = {sec}^{2} \theta}$

What we know is our tangent value. We are going to use the tan²θ+1 = sec²θ to find the value of cosθ. Substitute tanθ = 4 in the second identity.

$\large{ {4}^{2} + 1 = {sec}^{2} \theta } \\ \large{16 + 1 = {sec}^{2} \theta } \\ \large{ {sec}^{2} \theta = 17}$

As we know, sec²θ = 1/cos²θ.

$\large \boxed{sec \theta = \frac{1}{cos \theta} } \\ \large \boxed{ {sec}^{2} \theta = \frac{1}{ {cos}^{2} \theta} }$

And thus,

$\large{ {cos}^{2} \theta = \frac{1}{17}} \\ \large{cos \theta = \frac{ \sqrt{1} }{ \sqrt{17} } } \\ \large{cos \theta = \frac{1}{ \sqrt{17} } \longrightarrow \frac{ \sqrt{17} }{17} }$

Since the given domain is 180° < θ < 360°. Thus, the cosθ < 0.

$\large{cos \theta = \cancel\frac{ \sqrt{17} }{17} \longrightarrow cos \theta = - \frac{ \sqrt{17} }{17}}$

Then use the Identity of sinθ = tanθcosθ to find the sinθ.

$\large{sin \theta = 4 \times ( - \frac{ \sqrt{17} }{17}) } \\ \large{sin \theta = - \frac{4 \sqrt{17} }{17} }$

Answer

sinθ = -4sqrt(17)/17 or A choice.

4 0

3 years ago

A number squared times four is equal to 16. Find the missing number.

erica [24]

The answer should be 2

6 0

3 years ago

What is the quotient of 6 and 2? ? -12. 1 12. 0 12. 0 12.

Julli [10]

To find the quotient you do 6/ (-1/2). You keep, change, flip when dealing with fractions.

7 0

3 years ago

A cube has a net with area 600 in2. How long is an edge of the cube?

aev [14]

Answer : The length of an edge of cube is, 10 inches.

Step-by-step explanation :

The formula used for area of cube is:

Area of cube = $6a^2$

where,

a = edge

We are given that:

Area of cube = $600in^2[tex]Now put all the given values in the above formula, we get:Area of cube = [tex]6a^2$

$600in^2=6a^2$

$a=10inches$

Therefore, the length of an edge of cube is, 10 inches.

3 0

3 years ago

Are these figures below similar? NO LINKS!! NEED ANSWER ASAP​

Are these figures below similar? NO LINKS!! NEED ANSWER ASAP