Write down the temperature shown?

What is the simplified expression for the expression below? 4(3x – 2) + 6x(2 – 1)

igor_vitrenko [27]

Step-by-step explanation:

4(3x-2) + 6x(2-1)

10x + 11x

21x

8 0

3 years ago

I DON'T WANT TO GO TO SUMMER SHCOOL, IF I FAIL I GET SUMMER SHCOOL, PLEASE HELP, IF YOU HAVE ANY KNOWLEDGE ON THIS TEACH ME OR S

jenyasd209 [6]

Answer:

B. 225 π sq. units

Step-by-step explanation:

the diameter of circle = √18²+24²

=√324+576=√900 = 30

the radius = ½×30=15

the area of circle =

π × 15² = π × 225 = 225 π sq. units

8 0

3 years ago

Translate the triangle left 1 units and up 5 units. What are the coordinates of point C after the translation?

Step2247 [10]

Answer:

b++nfr

Step-by-step explanation:

jjkiki

5 0

3 years ago

Read 2 more answers

*Asymptotes*<br> g(x) =2x+1/x-3 <br><br> Give the domain and x and y intercepts

Nataly [62]

Answer: Assuming the function is $g(x)=\frac{2x+1}{x-3}$ :

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The horizontal asymptote is $y=2$ .

The vertical asymptote is $x=3$ .

Step-by-step explanation:

I'm going to assume the function is: $g(x)=\frac{2x+1}{x-3}$ and not $g(x)=2x+\frac{1}{x}-3$ .

So we are looking at $g(x)=\frac{2x+1}{x-3}$ .

The x-intercept is when y is 0 (when g(x) is 0).

Replace g(x) with 0.

$0=\frac{2x+1}{x-3}$

A fraction is only 0 when it's numerator is 0. You are really just solving:

$0=2x+1$

Subtract 1 on both sides:

$-1=2x$

Divide both sides by 2:

$\frac{-1}{2}=x$

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is when x is 0.

Replace x with 0.

$g(0)=\frac{2(0)+1}{0-3}$

$y=\frac{2(0)+1}{0-3}$

$y=\frac{0+1}{-3}$

$y=\frac{1}{-3}$

$y=-\frac{1}{3}$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The vertical asymptote is when the denominator is 0 without making the top 0 also.

So the deliminator is 0 when x-3=0.

Solve x-3=0.

Add 3 on both sides:

x=3

Plugging 3 into the top gives 2(3)+1=6+1=7.

So we have a vertical asymptote at x=3.

Now let's look at the horizontal asymptote.

I could tell you if the degrees match that the horizontal asymptote is just the leading coefficient of the top over the leading coefficient of the bottom which means are horizontal asymptote is $y=\frac{2}{1}$ . After simplifying you could just say the horizontal asymptote is $y=2$ .

Or!

I could do some division to make it more clear. The way I'm going to do this certain division is rewriting the top in terms of (x-3).

$y=\frac{2x+1}{x-3}=\frac{2(x-3)+7}{x-3}=\frac{2(x-3)}{x-3}+\frac{7}{x-3}$

$y=2+\frac{7}{x-3}$

So you can think it like this what value will y never be here.

7/(x-3) will never be 0 because 7 will never be 0.

So y will never be 2+0=2.

The horizontal asymptote is y=2.

(Disclaimer: There are some functions that will cross over their horizontal asymptote early on.)

6 0

3 years ago

30 POINTS PLEASE HELP;)

AveGali [126]

Answer:

Lorsque vous montez dans la voiture et sortez de l'aéroport, tournez à gauche. Lorsque vous arrivez à la bifurcation de la route, tournez à droite. Ensuite, vous continuerez à avancer. Vous devrez faire deux virages à gauche. À droite, vous verrez ma maison.

Step-by-step explanation: I had a similar project so I used mine as an example and I rewrote it. Hope this helps

Translation : When you first get in the car and exit the airport turn left. When you get to the fork in the road turn right. Then you will keep driving forward. You will have to make two left turns. To the right you will see my house.

Feel free to change up some words if you need to

5 0

3 years ago