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chubhunter [2.5K]
3 years ago
13

Seven of the 10 children at Art can't make an average of 8 paintings. The remaining children make an average of 12 paintings. Wh

at is the average number of paintings made by children that are Camp. Enter your answer in the Box
Mathematics
1 answer:
goldenfox [79]3 years ago
6 0
Total number paintings made by category of 7 children = 7*8 = 56
Total number of paintings made by the remaining = 3*12 = 36

Total number of  paintings = 56+36= 92 paintings

Average number of paintings by all the children = 92/10 = 9.2 ≈ 9 paintings
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Which expression is equivalent to *picture attached*
DiKsa [7]

Answer:

The correct option is;

4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3  \left (\dfrac{50(51) }{2} \right )

Step-by-step explanation:

The given expression is presented as follows;

\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3  \right )

Which can be expanded into the following form;

\sum\limits _{n = 1}^{50} \left (4\cdot n^2 + 3  \cdot n\right ) = 4 \times \sum\limits _{n = 1}^{50} \left  n^2 + 3  \times\sum\limits _{n = 1}^{50}  n

From which we have;

\sum\limits _{k = 1}^{n} \left  k^2 = \dfrac{n \times (n+1) \times(2n+1)}{6}

\sum\limits _{k = 1}^{n} \left  k = \dfrac{n \times (n+1) }{2}

Therefore, substituting the value of n = 50 we have;

\sum\limits _{n = 1}^{50} \left  k^2 = \dfrac{50 \times (50+1) \times(2\cdot 50+1)}{6}

\sum\limits _{k = 1}^{50} \left  k = \dfrac{50 \times (50+1) }{2}

Which gives;

4 \times \sum\limits _{n = 1}^{50} \left  n^2 =  4 \times \dfrac{n \times (n+1) \times(2n+1)}{6} = 4 \times \dfrac{50 \times (50+1) \times(2 \times 50+1)}{6}

3  \times\sum\limits _{n = 1}^{50}  n = 3  \times \dfrac{n \times (n+1) }{2} = 3  \times \dfrac{50 \times (51) }{2}

\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3  \right ) = 4 \times \dfrac{50 \times (50+1) \times(2\times 50+1)}{6} +3  \times \dfrac{50 \times (51) }{2}

Therefore, we have;

4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3  \left (\dfrac{50(51) }{2} \right ).

4 0
3 years ago
I need help with the answer
solmaris [256]

Answer:

Its the last option

y = 1488.33x + 23800 ; $172,600.

Step-by-step explanation:

The slope of the trend line = (median value for 2000 - median value for 1940) / 60

= 89300 / 60

= 1488.33.

So the equation is 1488.33x + 23,800

Estimate for 2040

is 1483.33* 100 + 23800

= 172,600.

5 0
3 years ago
If the measures of two angles of a triangle are 95 and 14°, what is the measure of the third angle?​
marin [14]

Answer:

71°

Step-by-step explanation:

95° + 14° = 109°

180° in a triangle

180° - 109° = 3rd angle = 71 °

3 0
2 years ago
Read 2 more answers
the ratio of peters money to henrys money is 4 : 3 there at first. after perter spent 12 dollars they had an equal amount of mon
MatroZZZ [7]

Using a system of equations, it is found that Peter had $48 at first.

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are:

  • Variable x: Peter's money.
  • Variable y: Henry's money.

The ratio of peters money to henrys money is 4 : 3, hence:

\frac{x}{y} = \frac{4}{3}

After Peter spent $12, they had the same amount, hence:

y = x - 12.

Then, replacing in the ratio:

\frac{x}{y} = \frac{4}{3}

\frac{x}{x - 12} = \frac{4}{3}

4(x - 12) = 3x

x = 48.

More can be learned about a system of equations at brainly.com/question/24342899

#SPJ1

4 0
2 years ago
H(h+4) monomial times polynomial
Fofino [41]
Distribute the h:

h(h+4)
h*h + 4*h
h² + 4h

Hope this helps!
4 0
3 years ago
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