Between what two integers does 160 lie
1 answer:
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Answer:
see explanation
Step-by-step explanation:
I will begin with part two, first.
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius.
Given
x² - 18x + y² - 10y = - 6
Using the method of completing the square
add ( half the coefficient of the x/ y terms )² to both sides
x² + 2(- 9)x + 81 + y² + 2(- 5)y + 25 = - 6 + 81 + 25, that is
(x - 9)² + (y - 5)² = 100 ← in standard form
with centre = (9, 5 ) and r = = 10
Answer:
The first number is 138.
Step-by-step explanation:
Let the first number be <em>x.</em>
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Then since they are consecutive numbers, the second number will be (<em>x</em> + 1), the third (<em>x</em> + 2), the fourth (<em>x</em> + 3) and the fifth being (<em>x</em> + 4).
We are given that their sum is 700. Therefore:
Solve for <em>x</em>. Combine like terms:
Subtract 10 from both sides:
Divide both sides by five. Therefore:
The first number is 138.