Answer:
Check the explanation
Explanation:
1) supposing the keystream is a stream that is of random bits in Z26, we can describe a stream cipher based on the Latin Alphabet that is as follows (where A ↔ 0, B ↔ 1, C ↔ 2 etc):
mod26
mod26
2)
= ” B ” − ” R ” = 1 − 17 = − 16 ≡ 10 mod 26 = ” K ” etc ·
The Decrypted Text is: ”KASPAR HAUSER”
Answer:
<u>BEST</u>
Option 4
<u>WORST</u>
2
Explanation:
Option 4 is the best cus confronting is better than just watching and letting it happen which in option 2 that's the case
CFAA is an acronym that stands for Computer Fraud and Abuse Act. It is an anti-hacking bill that was passed to amend an existing computer fraud law. It aims to strengthen cyber security by forbidding access to computers without authorization.
People do have reasons why they want to work for a particular company. It may be due to what they company stands for, what they make or about your dream.
I can therefore say that I want to work for Rev because they are revolutionizing the industry and I want to be part of the change process.
<h3>How do you answer why do you want to work?</h3>
Note that when looking for a job, job experience do matter. When ask the reason for looking for this job.
One can answer that they have the experience or the needed expertise and skills required for this job as they want to be aligned with what the company stands for.
Learn more about work from
brainly.com/question/25573309
Answer:
Explanation:
The following code is written in Python. It creates a method for each one of the questions asked and then tests all three with the same test case which can be seen in the picture attached below.
def alternating_list(lst1, lst2):
lst3 = []
for x in range(len(lst1)):
lst3.append(lst1[x])
try:
lst3.append(lst2[x])
except:
pass
if len(lst2) > len(lst1):
lst3.extend(lst2[len(lst1):])
return lst3
def reverse_alternating(lst1, lst2):
lst3 = []
if len(lst1) == len(lst2):
for x in range(len(lst1) - 1, -1, -1):
lst3.append(lst1[x])
lst3.append(lst2[x])
return lst3
def alternating_list_no_extra(lst1, lst2):
lst3 = []
max = 0
if len(lst1) > len(lst2):
max = len(lst2)
else:
max = len(lst1)
for x in range(max):
lst3.append(lst1[x])
try:
lst3.append(lst2[x])
except:
pass
return lst3
