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maksim [4K]
3 years ago
6

Angel and jayden where in track practice . the track is 2/5 kilometers around.

Mathematics
1 answer:
Luden [163]3 years ago
3 0
Distance equals velocity times time.

d=vt

v=d/t

v=(3*2/5)km/5min

v=(6/5)/5

v=6/25 km/min

v=0.24 km/min
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This is due today please help! 15points!
aalyn [17]

Answer:

17x +215/ 5

Step-by-step explanation:

17x +215

     5

3 0
3 years ago
Read 2 more answers
21. Carrie withdraws $10 from her account each day for 7 days.
Fiesta28 [93]

Answer:

a.70. b.50

Step-by-step explanation:

  • If Cartie takes $10 from her account for 7 days she would have taken $70 out.

7 \times 10 = 70

  • Next we look at the net problem it is asking us how much is left we already know from the equation above that we need to subtract 70 from 120
  • 70 - 120 = 50
  • We now have both answers A. being that she would have taken $70 in total out of her account and B. being that she would have $50 left in her account.
3 0
3 years ago
Nick starts with 20 milligrams of a radioactive substance. The amount of the substance decreases by 14 each week for a number of
zlopas [31]

Answer:

Eric's expression is :

20(\frac{1}{4})^w

and Andrea's is :

(1-0.5)^w

In Eric's expression, 20 represents the initial amount of substance with which he has started the experiment. \thinspace \frac{1}{4}\thinspace is the amount of substance left after each time period (in this case, each week).The variable w in this case represents the number of weeks.

Andrea's expression can be written as :

1\cdot (1-0.5)^w

The one outside of parentheses represents the initial amount of the substance. The one inside of parentheses represents 100% of the original amount of the substance. 0.5 represents the 50% of the substance that is lost each time period. The variable w in this case represents the number of weeks.

8 0
3 years ago
Read 2 more answers
Find the area of the region that lies inside the first curve and outside the second curve. r = 6 − 6 sin θ, r = 6
yan [13]
Each curve completes one loop over the interval 0\le t\le2\pi. Find the intersections of the curves within this interval.

6-6\sin\theta=6\implies 1-\sin\theta=1\implies \sin\theta=0\implies \theta=0,\theta=\pi

The region of interest has an area given by the double integral

\displaystyle\int_\pi^{2\pi}\int_6^{6-6\sin\theta}r\,\mathrm dr\,\mathrm d\theta

equivalent to the single integral

\displaystyle\frac12\int_\pi^{2\pi}\bigg((6-6\sin\theta)^2-6^2\bigg)\,\mathrm d\theta

which evaluates to 9\pi+72.

8 0
3 years ago
Which number belong to the set of the inequality 22x=902? check all that apply​
Elis [28]

Answer:

Step-by-step explanation:

23

4 0
3 years ago
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