14c³d²-21c²d³/14cd
= (196c^4d³-21c²d³)/ 14cd
= (196c³d²-21cd²)/14
= (28c³d²-3cd²)/2
I hope that's help !
Ok so there is 60 minutes in an hour and you have 107 minutes so
107-60 = 47 ( 60 has become an hour)
So we are left with 47 minutes, so add the hour to 7:45 which will make it 8:45 pm
Then add 15 to make it 9:00 pm ( 47 - 15 = 32)
And so then add 32 minutes to 9:00 pm
Answer is 9:32 p.m.
Answer:
b=6
Step-by-step explanation:
Change the equation, x - y = -3, to isolate x or y and plug that new equation into the equation 2x + 3y = 4
I changed it to: x = y - 3
so
2(y - 3) + 3y = 4
2y - 6 + 3y = 4
5y - 6 = 4
5y = 4 + 6
5y = 10
y = 10/5
y = 2
then you plug that 2 into the equation x = y - 3 to get the value of x
x = (2) - 3
x = -1
you can check this by plugging the x and y values into the equation 2x + 3y = 4
2(-1) + 3(2) = 4
-2 + 6 = 4
4 = 4
hope this helps :)
<span>=<span><span><span><span><span><span><span>2x</span>+<span>−<span>8x</span></span></span>+<span>−<span>6y</span></span></span>+9</span>+<span>−14</span></span>+x</span>+<span>11y
</span></span></span><span>=<span><span><span>(<span><span><span>2x</span>+<span>−<span>8x</span></span></span>+x</span>)</span>+<span>(<span><span>−<span>6y</span></span>+<span>11y</span></span>)</span></span>+<span>(<span>9+<span>−14</span></span><span>)
= -5x+5y+-5
= -5x+5y-5
Answer is = -5x+5y-5
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