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lara [203]
3 years ago
7

Simplify 2 x - 8 x - 6 y + 9 -14 + x + 11 y.

Mathematics
2 answers:
Lunna [17]3 years ago
8 0
<span>=<span><span><span><span><span><span><span>2x</span>+<span>−<span>8x</span></span></span>+<span>−<span>6y</span></span></span>+9</span>+<span>−14</span></span>+x</span>+<span>11y

</span></span></span><span>=<span><span><span>(<span><span><span>2x</span>+<span>−<span>8x</span></span></span>+x</span>)</span>+<span>(<span><span>−<span>6y</span></span>+<span>11y</span></span>)</span></span>+<span>(<span>9+<span>−14</span></span><span>)

= -5x+5y+-5

= -5x+5y-5

Answer is = -5x+5y-5

</span></span></span></span>
Pachacha [2.7K]3 years ago
7 0

the correct answer is B: -5 x + 5 y - 5

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The anwser is 1,4

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A = {a, b, c, d}
Helen [10]

Answer:

Johnny is wrong.

A \cup B = \left\{a,b,c,d,e,f,g,h\right\}

Step-by-step explanation:

Johnny is wrong.

A better definition would be: A \cup B is the set of all elements that belong to at least one A or B.

So, the elements that belong to both A and B, like c and d in this exercise, also belong to A \cup B.

So:

A \cup B=\left\{a,b,c,d,e,f,g,h\right\}

4 0
3 years ago
Find the coordinates of point z such that the ratio of fz to zd is 5;3
Vilka [71]

The point such that the coordinate is 5;3 is (14, 0)

<h3>Midpoint of coordinates using ratio</h3>

The formula for finding the midpoint of a line in the ratio m:n is expressed as:

M(x, y) = {(mx₁+nx₂)/2, (my₁+ny₂)/2,}

Given the coordinate of G and D on the line as G(5, 0) and D(1,0)

Since there is no y-axis, hence;

x = 5(5)+1(3)/2

x = 25+3/2

x = 28/2

x =14

Hence the point such that the ratio is 5;3 is (14, 0)

Learn more on midpoint of a line here: brainly.com/question/5566419

#SPJ1

8 0
1 year ago
Find values a and b that satisfy a∙〈5,-4,0〉+b∙〈2,2,-3〉=〈11,-16,-6〉.
WARRIOR [948]

The right hand side of the equation is 〈11 , -16 , 6〉

The values of a and b are a = 3 , b = -2

Step-by-step explanation:

If n . <a , b> + m . <c , d> = < x , y>, then

  • na + mc = x
  • nb + md = y

∵ a  ∙〈5 , -4 , 0〉 + b ∙ 〈2 , 2 , -3〉 = 〈11 , -16 , 6〉

- By using the rule above

∴ a(5) + b(2) = 11 ⇒ (1)

∴ a(-4) + b(2) = -16 ⇒ (2)

∴ a(0) + b(-3) = 6 ⇒ (3)

Use equation (3) to find the value of b

∵ a(0) + b(-3) = 6

∴ 0 - 3b = 6

∴ -3b = 6

- Divide both sides by -3

∴ b = -2

Substitute b in equation (1) or equation (2) to find a

∵ a(5) + b(-2) = 11

∴ 5a - 2b = 11

∵ b = 2

∴ 5a - 2(2) = 11

∴ 5a - 4 = 11

- Add 4 to both sides

∴ 5a = 15

- Divide both sides by 5

∴ a = 3

To check your answer substitute a and b in equation (2)

∵ a(-4) + b(2) = -16

∴ -4a + 2b = -16

∵ a = 3 , b = -2

∵ The left hand side is -4a + 2b = -4(3) + 2(-2) = -12 - 4 = -16

∵ The right hand side is -16

∴ L.H.S = R.H.S

∴ The values of a and b are 3 , -2

The values of a and b are a = 3 , b = -2

Learn more:

You can learn more about the equations in brainly.com/question/11306893

#LearnwithBrainly

8 0
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