Answer:
All points on line CD are equidistant from A and B
Step-by-step explanation:
Given that point A is the center of circle A and point B is the center of circle B, and the circumference of circle A passes through the center of circle B which is point B and vice versa.
Therefore we have;
The radius of circle A = The radius of circle B
Which gives;
The distance of the point C to the center A is equal to the distance of the point C to the center B
Similarly, the distance of the point D to the center A is equal to the distance of the point D to the center B
So also the distances of all points on the line from the center A is equal to the distances of all points on the line from the center B.
8 over 9
= 8/9
= 8:9
Final answer: 8:9~
The First Graph represents the situation.
The runner goes a lot of distance in a short amount of time (Demonstrated by the steep incline of the first portion). When the runner is tying their shoe, the distance remains the same, thus eliminating the second graph and the last graph because the last graph doesn't show the beginning of the problem. Finally, we know that the runner is slower after tying their shoe, this means the incline of the line would be far less as steep (Meaning the slope would be smaller). The only graph that depicts all of these, is the first one.
I Hope this Helps!
-Sinnamin
Answer:
Step-by-step explanation:
1 - 8
2 - 14
3 - 22
Answer: correct answer is D.
Step-by-step explanation:
