Answer:
14.2 L H2S
Explanation:
Mole ratio
2 mol H2S:2 mol SO2
We are just looking for volume, so the required amount is the same as the produced amount as long as the mole ratio is balanced.
E°cell =+1.34V
F= 96485C mol-1
3Cu(s) →3CU2+(aq) +6e-E°ck= -0.34V
2MnO4-(aq) +8H+(aq)+6e→2MnO2(s)+4H2O(l)/3CU(s) + 2MnO4-(aq)+8H+(aq)→3CU 2+((aq)+ 2MnO2(s)+4H2O (l)
E°red= +1.68V/E°cell=+1.34V
ΔG° = -nFE°cell = -6×96485×1.34 = -775.7kJ/mol