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Rasek [7]
3 years ago
13

The molecular mass of air, at standard pressure and temperature, is approximately 28.97 g/mol. Calculate the mass of 3.33 moles

of air.
First, complete the unit conversion using dimensional analysis:

A ×
B
C
= ? g Air

A:
B:
Chemistry
2 answers:
erica [24]3 years ago
8 0

A: 3.33 mol Air

B: 28.97 g Air

C: 1 mol Air

poizon [28]3 years ago
6 0
<h3>Answer:</h3>

               Mass = 96.47 g

<h3>Solution:</h3>

Data Given:

                  M.Mass  =  28.97 g.mol⁻¹

                  Moles  =  3.33 mol

                  Mass  =  ??

Formula Used:

                  Moles  =  Mass ÷ M.Mass

Solving for Mass,

                  Mass  =  Moles × M.Mass

Putting values,

                  Mass  =  3.33 mol × 28.97 g.mol⁻¹

                  Mass  =  96.4701 g

Rounding to four significant numbers,

                 Mass = 96.47 g


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guapka [62]

Answer:

M_{K^+}=4.0M \\\\M_{SO_4^{2-}}=2.0M

Explanation:

Hello!

In this case, since the molarity of a solution is defined as the moles of solute divided by the volume of solution liters, given the mass of potassium sulfate, we can compute the moles by using its molar mass (174.24 g/mol):

n_{K_2SO_4}=87gK_2SO_4*\frac{1molK_2SO_4}{174.27gK_2SO_4} =0.50molK_2SO_4

Thus, since one mole of potassium sulfate has two moles of potassium ions (K₂) and one mole of sulfate ions, we can compute the moles of each ion as shown below:

n_{K^+}=0.50molK_2SO_4*\frac{2molK^+}{1molK_2SO_4}=1.0molK^+\\\\ n_{SO_4^{2-}}=0.50molK_2SO_4*\frac{1molSO_4^{2-}}{1molK_2SO_4}=0.50molSO_4^{2-}\\

In such a way, the molarity of each ion turns out:

M_{K^+}=\frac{1.0mol}{0.250L}=4.0M \\\\M_{SO_4^{2-}}=\frac{0.5mol}{0.250L}=2.0M

Best regards!

5 0
3 years ago
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bazaltina [42]
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Answer:

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may this helps you

hope it's correct

bye

4 0
3 years ago
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