How is stoichiometry used to calculate the amount of product from amount of reactant?

Chemistry

2 answers:

Nesterboy [21]3 years ago

7 0

Stoichiometry relates moles of rectant to moles of product

IceJOKER [234]3 years ago

6 0

<span>Stoichiometry deals with the quantitative measurement of reactants and products in a chemical reaction. Let suppose you are given with following reaction;

A + 2 B </span>→ 3 C

According to this reaction 1 mole of A reacts with 2 moles of B to produce 3 moles of C. Now using the concept of mole one can easily measure the amount of reactants reacted and the amount of product formed, as...

1 Mole Exactly equals 6.022 × 10²³ particles

1 Mole of Gas (at STP) exactly occupies 22.4 L Volume

1 Mole of any compound exactly equals the molar mass in grams

Therefore, <span>Stoichiometry is very helpful in quantitative analysis.</span>

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Which is the best way to determine if an object is made of pure gold?

netineya [11]

Answer:

Acid?

Explanation:

3 0

4 years ago

Without looking at the periodic table, identify the group, period, and

kobusy [5.1K]

the group : 2

periode : 6

block = 2

atomic number = 56

<h3>Further explanation </h3>

We can divide the periodic system into several parts:

1. Block s: groups 1 and 2 (having a configuration of 1s-7s) consist of active metals except for H (non-metals) and He (noble gases)

2. Block p: group 13-18 (has a 2p-6p configuration), also called a representative element because it includes metals, non-metals and metalloids

3. Block d: group 3-12 (having the 3d-6d configuration), are transition metal elements

4. Block f: Lanthanides and Actinides (having a 4f-5f configuration), are inner transition elements that are also metal

The element with the electron configuration : [Xe]6s²

The outer shell 6s² :

Electron configuration :

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s² : electron =56

group⇒valence electron ⇒2

period⇒the greatest value of the quantum number n⇒6

The element that is in period 6, and belongs to group 2 and has the atomic number 56 and in the block s

4 0

3 years ago

If 185 g of KBr are dissolved in 1.2 kg of water, what would be the expected change in boiling point? The boiling point constant

Fudgin [204]

Answer:

ΔTb = 0.66 C

Explanation:

Given

Mass of KBr = 185 g

Mass of water = 1.2 kg

Kb = 0.51 C/m

Explanation:

The change in boiling point (ΔTb) is given by the product of molality (m) of the solution and the boiling point constant (Kb)

$\Delta T_{b}= K_{b}* m$

$Molality = \frac{moles\ KBr}{Kg\ water} \\\\moles KBr = \frac{mass\ KBr}{Mol.wt\ KBr} = \frac{185}{119} = 1.555\\\\Molality (m) = \frac{1.555 }{1.2} =1.296 m\\$