Explanation:
The given reaction at cathode will be as follows.
At cathode: , = -0.761 V
At anode: , = 0.761
Therefore, net reaction equation will be as follows.
Initial: 0.129 - - 0.427
Change: -0.047 - - -0.047
Equilibrium: (0.129 - 0.047) (0.427 - 0.047)
= 0.082 = 0.38
As for the given reaction is zero.
Hence, equation for calculating new cell potential will be as follows.
E_{cell} =
=
= 0.019
Thus, we can conclude that the cell potential of the given cell is 0.019.
Answer:
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Explanation:
Answer:
The balanced equations for the reactions are outlined below:
Explanation:
A balanced equation describes how many (number of moles) atoms of the reactant give rise to how many (number of moles) of product.
- Hydrogen sulfide gas () and oxygen gas () react to produce sulfur dioxide gas () and water vapor gas.
- The balanced equation for the reaction, taking into consideration the states is:
→
Vanadium(II) oxide (VO) is oxidized by iron(III) oxide (Fe2O3) resulting in the formation of vanadium(V) oxide (V2O5) and iron(II) oxide (FeO).
The balanced equation:
→
The answer for this would be 69.6
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Explanation: The respiratory pigment, haemoglobin in red blood cells have a very high affinity of oxygen. It combines with oxygen to form oxyhaemoglobin and thus oxygen is carried from lungs to various body parts. Carbondioxide is highly soluble in water so it is mostly transported in dissolved form in our blood plasma.