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anyanavicka [17]
4 years ago
13

One-fourth of a number is five-eighths. Find the number.

Mathematics
1 answer:
ioda4 years ago
4 0

Answer:

5/32

Step-by-step explanation:

Since 5/8 x 1/4 = 5/32, that is the answer.

Key Note: When you get this type of question, multiply the second  umber by the first.

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Find the x- and y- intercepts of the equation 7x+ 14 y=28
7nadin3 [17]

Chapter : Linear equations

Lesson : Math for Junior High School

7x + 14y = 28

if want to find x and y, we must substitution value 0 to the equation x and y :

# If x = 0, then :

7x + 14y = 28

= 7(0) + 14y = 28

= 0 + 14y = 28

= 14y = 28 → y = 28/14

= y = 2

# If y = 0, then :

7x + 14y = 28

= 7x + 14(0) = 28

= 7x + 0 = 28

= 7x = 28 → x = 28 / 7

= x = 4

and that result was proven x = 4 and y = 2

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3 years ago
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e-lub [12.9K]
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3 years ago
Could someone help me? ASAP!!
Wewaii [24]

Answer:

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Slope intercept form

8 0
3 years ago
The function ƒ(x) = (x − 1)^2 + 5 is not one-to-one. Find a portion of the domain where the function is one-to-one and find an i
melisa1 [442]

Answer:

f(x)=(x-1)^2+5 with domain x>1 and range y>5 has inverse g(x)=sqrt(x-5)+1 with domain x>5 and range y>1.

Step-by-step explanation:

The function is a parabola when graphed. It is in vertex form f(x)=a(x-h)^2+k where (h,k) is vertex and a tells us if it's reflected or not or if it's stretched. The thing we need to notice is the vertex because if we cut the graph with a vertical line here the curve will be one to one. So the vertex is (1,5). Let's restrict the domain so x >1.

* if x>1, then x-1>0.

* Also since the parabola opens up, then y>5.

So let's solve y=(x-1)^2+5 for x.

Subtract 5 on both sides:

y-5=(x-1)^2

Take square root of both sides:

Plus/minus sqrt(y-5)=x-1

We want x-1>0:

Sqrt(y-5)=x-1

Add 1 on both sides:

Sqrt(y-5)+1=x

Swap x and y:

Sqrt(x-5)+1=y

x>5

y>1

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3 years ago
The difference bewteen -58 - 40
Korolek [52]

Answer:

-98

Step-by-step explanation:

3 0
4 years ago
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