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Licemer1 [7]
3 years ago
11

Am i correct?? * show examples & details if i am incorrect!!! (: *

Mathematics
1 answer:
EastWind [94]3 years ago
6 0
You are correct! :)))))
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A table is 3 feet and 2 inches wide and a chair is 25 inches wide how much wider is the table then chair in inches
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To answer this problem, you would need to convert the values into inches.
12 inches = 1 ft

Table = 3ft 2 in = 38 inches wide
Chair = 25 inches wide

Then just subtract the two values to find how much wider the table is than the chair.

38-25=13 inches wider
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(x^2-y^2)^2\\\\\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\=(x^2)^2-2(x^2)(y^2)+(y^2)^2\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=x^4-2x^2y^2+y^2\\-----------------------------

\text{Other solution}\\\\(x^2-y^2)^2\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\= [(x-y)(x+y)]^2\\\\\text{use}\ (ab)^n=a^nb^n\\\\=(x-y)^2(x+y)^2

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