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2 years ago

14

Justin runs at a constant rate, traveling 17km in 2 hours. Write an equation that shows the relationship between the distance he

runs (d) in kilometers and the time he spends running (h) in hours.

2 answers:

Sladkaya [172]2 years ago

7 0

17 km / 2 hours = 8.5 km per hour

equation: d = 8.5h

VikaD [51]2 years ago

5 0

Answer:

d=8.5h

Step by Step Explanation:

I just did Khan Academy.

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Do i solve this?? need help???

Arlecino [84]

A =
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3 years ago

Whats the answer for number 3

Karolina [17]

cant see the full question ;/

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3 years ago

PLEASE HELP!!<br>1y+14=-4y+9 for y. Round your answer to the nearest tenth.

slega [8]

Answer:

y = -1.0

Step-by-step explanation:

Isolate the variable, y. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

PEMDAS is the order of operations, and =

Parenthesis

Exponents (& Roots)

Multiplication

Division

Addition

Subtraction

First, add 4y and subtract 14 from both sides:

1y (+4y) + 14 (-14) = -4y (+4y) + 9 (-14)

1y + 4y = 9 - 14

Combine like terms:

5y = -5

Isolate the variable, y. Divide 5 from both sides:

(5y)/5 = (-5)/5

y = -5/5

y = -1

y = -1 is your answer.

~

6 0

3 years ago

How would you determine what fraction strips with rhe same denominator would fit exactly under 1/2 & 1/3. What are they?

vfiekz [6]

Step-by-step explanation:

$\frac{1}{2} = \frac{1 \times 3}{2 \times 3} = \frac{1}{6} \\ \\ \frac{1}{3} = \frac{1 \times 2}{3 \times 2} = \frac{1}{6}$

${ \boxed{{ \bold{{ \pink{e}}{ \blue{x}}{ \purple{p}}{ \green{l}}{ \red{a}}n{ \purple{a}}{ \orange{t}}{ \red{i}}on}}}}$

we equate first under the fraction (denominator)
find the number of products that allow the denominators to be the same
the result that both fractions have the same denominator

<h3>Answer Details</h3>

Lesson : Math
Grade : 4

#I hope this helps°^°

6 0

3 years ago

Simply 6-4 root 3/ 6+4 root 3 by ratnolising the denominator

Inessa [10]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

the question asks us to rationalise the given expression !

so let's start ~

$\frac{6 - 4 \sqrt{3} }{6 + 4 \sqrt{3} } \\ \\ \implies \: \frac{6 - 4 \sqrt{3} }{6 + 4 \sqrt{3} } \: \times \: \frac{6 - 4 \sqrt{3} }{6 - 4 \sqrt{3} } = \frac{(6 - 4 \sqrt{3}) {}^{2} }{6 {}^{2} - 4 \sqrt{3} {}^{2} } \\ \\ \implies \frac{\: 6 {}^{2} + 4 \sqrt{3} {}^{2} - (2 \times 6 \times 4 \sqrt{3} )}{36 - 48} \\ \\ \implies \: \frac{36 + 48 - 48 \sqrt{3} }{ - 12} \\ \\ \implies \: \frac{84 + 48 \sqrt{3} }{ - 12} \\ \\ \implies \: \frac{ \cancel{- 12}(7 - 4 \sqrt{3} )}{ \cancel{ - 12} } \\ \\ \implies \: 7 - 4 \sqrt{3}$

hope helpful :D

3 0

2 years ago

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