Answer:
The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.
Step-by-step explanation:
Consider the provided information.
A chemical flows into a storage tank at a rate of (180+3t) liters per minute,
Let 
is the amount of chemical in the take at <em>t </em>time.
Now find the rate of change of chemical flow during the first 20 minutes.
![\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%7B20%7D_%7B0%7D%20%7Bc%27%28t%29%7D%20%5C%2C%20dt%20%3D%5Cleft%5B180t%2B%5Cdfrac%7B3%7D%7B2%7Dt%5E2%5Cright%5D%5E%7B20%7D_0)
So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.
Answer:
286 2/3 km
Step-by-step explanation:
Recalling that 1 hour = 60 minutes, we convert '3 hours 35 minutes' to
3 + (35/60) hours, or 3 35/60 hours, or 3.5833 hours.
Since distance = (rate)(time),
the distance driven by tim is (80 km/hr)(3.5833 hrs) = 286 2/3 km
Answer:
It has 0 distinct real number zeros. The function does not touch the x-axis
Answer:
C.) 4
Step-by-step explanation:
y2 - y1/x2 - x1
m = 160 - 80/60 - 40
m = 80/20
m = 8/2
m = 4/1
m = 4
