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Arte-miy333 [17]
3 years ago
5

What are the properties of water that make it unique

Chemistry
1 answer:
Vaselesa [24]3 years ago
3 0

Answer:

Water is polar.

Water is an excellent solvent.

Water has a high heat capacity.

Water has a high heat of vaporization.

Water has cohesive and adhesive properties.

Water is less dense as a solid than as a liquid.

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What is the minimum amount of 6.0 M H2SO4H2SO4 necessary to produce 25.0 g of H2(g)H2(g) according to the reaction between alumi
Lelechka [254]

2.083 Liters of 6.0 M solution sulfuric acid is required. This solved using molecular calculations and Titration.

Solution: 2Al(s)+3H_2SO_4(aq) = Al_2(SO_4)_3(aq)+3H_2(g)

Moles of hydrogen gas =  \frac{25}{2} = 12.5 mol

Then 12.5 moles of hydrogen will be obtained from Moles of Sulfuric acid = 12.5 mol

Molarity of the sulfuric acid solution = 6.0 M = 6 mol/ l

6M = \frac{12.5 mole}{V}

where V is the volume needed

V = \frac{12.5}{6}

V = 2.083 l

<h3>What is Titration?</h3>
  • Titration, commonly referred to as titrimetry, is a typical quantitative chemical analysis method used in laboratories to ascertain the unidentified quantity of an analyte .
  • Titration is frequently referred to as volumetric analysis because it relies heavily on volume measurements. The titrant or titrator is a reagent that is prepared as a standard solution.
  • To determine concentration, a solution of the analyte or titrand reacts with a known concentration and volume of the titrant. The titration volume is the amount of titrant that has responded.
  • Titrations come in a variety of forms with various protocols and objectives. Redox and acid-base titrations are the two most typical types of qualitative titrations.

To learn more about titration with the given link

brainly.com/question/2728613

#SPJ4

8 0
2 years ago
Calculate the number of milliliters of 0.710 M Ba(OH)2 required to precipitate all of the Mn2+ ions in 161 mL of 0.796 M KMnO4 s
USPshnik [31]

<u>Answer:</u> The volume of barium hydroxide is 183 mL.

<u>Explanation:</u>

To calculate the moles of cadmium nitrate, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}       .....(1)

Molarity of MnSO_4 = 0.796 M

Volume of MnSO_4 = 161 mL = 0.161 L   (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

0.796mol/L=\frac{\text{Moles of }MnSO_4}{0.161L}\\\\\text{Moles of }MnSO_4=0.13mol

The chemical equation for the reaction of manganese sulfate and barium hydroxide follows:

MnSO_4(aq.)+Ba(OH)_2(aq.)\rightarrow Mn(OH)_2(s)+BaSO_4(aq.)

By Stoichiometry of the reaction:

1 mole of manganese sulfate reacts with 1 mole of barium hydroxide.

So, 0.13 moles of manganese sulfate will react with = \frac{1}{1}\times 0.13=0.13mol of barium hydroxide

Now, calculating the volume of barium hydroxide by using equation 1, we get:

Moles of barium hydroxide = 0.13 moles

Molarity of barium hydroxide = 0.710 M

Putting values in equation 1, we get:

0.710mol/L=\frac{0.13mol}{\text{Volume of barium hydroxide}}\\\\\text{Volume of barium hydroxide}=0.183L

Converting this into milliliters, we use the conversion factor:

1 L = 1000 mL

So, 0.183L=0.183\times 1000=183mL

Hence, the volume of barium hydroxide is 183 mL.

7 0
3 years ago
PLEASEEE HELPPP MEEE
andrezito [222]

Answer:

yes the one that is circled is correct

Explanation:

4 0
3 years ago
Read 2 more answers
A 25.0g sample of brass, which has a specific heat capacity of 0.375·J·g−1°C−1, is dropped into an insulated container containin
Angelina_Jolie [31]

Answer:

The equilibrium temperature of water is 25.6 °C

Explanation:

Step 1: Data given

Mass of the sample of brass = 25.0 grams

The specific heat capacity = 0.375 J/g°C

Mass of water = 250.0 grams

Temperature of water = 25.0 °C

The initial temperature of the brass is 96.7°C

Step 2: Calculate the equilibrium temperature

Heat lost = heat gained

Q(sample) = -Q(water)

Q = m*C* ΔT

m(sample)*c(sample)*ΔT(sample) = - m(water)*c(water)*ΔT(water)

⇒m(sample) = the mass of the sample of brass = 25.0 grams

⇒with c(sample) =The specific heat capacity = 0.375 J/g°C  

⇒with ΔT = the change of temperature = T2 - T1 =T2 - 96.7 °C

⇒with m(water) = the mass of the water = 250.0 grams

⇒with c(water) = the specific heat capacity = 4.184 J/g°C

⇒with ΔT(water) = the change of temperature of water = T2 - T1 = T2 - 25.0°C

25.0 * 0.375 * (T2 - 96.7) = - 250.0 * 4.184 J/g°C * (T2 - 25.0°C)

9.375T2 - 906.56 = -1046T2 + 26150

9.375T2 + 1046T2 = 26150 + 906.56

1055.375T2 = 27056.26

T2 = 25.6 °C

The equilibrium temperature of water is 25.6 °C

4 0
3 years ago
Which graph best shows an inverse relationship?
Ghella [55]

The graphs can be described as

So in case of inverse relationship we will obtain a curve not straight line


3 0
3 years ago
Read 2 more answers
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