Answer:
We are in Tropical Rainforests.
Explanation:
Biome is basically an ecological region of earth that has specific type of flora and fauna (plants and animals). Every biome has specific abiotic factors like specific climate, temperature, geology, vegetation, soils and relief.
There are total 8 biomes in the world
- Desert
- Grassland
- Temperate Boreal Forest
- Chaparral
- Tropical Savanna
- Tropical Rainforest
- Tundra
- Temperate Deciduous Forest
Now in our question, we have been given some conditions and are asked to identify the biome. The annual precipitation is about 300 cm and the average temperature is around 25 degrees Celsius.
Now, if we study the characteristics of all these biomes, it is very simple to identify that the biome is Tropical Rainforest.
Important characteristics of Tropical Rainforest:
- They receive more than 200 cm of rain each year.
- The temperature of the biome is between 20 degree Celsius and 25 degree Celsius during the whole year.
- Around 50 percent of the animal specie of the world are found here.
<em>Note: </em><em>You can study the characteristics of world’s other biomes in the link :
http://www.physicalgeography.net/fundamentals/9k.html
</em>
Hope it helps! :)
Explanation:
We will balance equation which describes the reaction between sulfuric acid and sodium bicarbonate: as follows.
Next we will calculate how many moles of
are present in 85.00 mL of 1.500 M sulfuric acid.
As, Molarity = 
1.500 M = 
n = 0.1275 mol
Now set up and solve a stoichiometric conversion from moles of
to grams of
. As, the molar mass of
is 84.01 g/mol.
= 21.42 g
So unfortunately, 15.00 grams of sodium bicarbonate will "not" be sufficient to completely neutralize the acid. You would need an additional 6.42 grams to complete the task.
Answer:
324.24 kPa
Explanation:
Given that;
Initial pressure P1 = 101325 Pa
V1= 400 ml
P2 = ?
V2= 125mL
From Boyle's law;
P1V1 = P2V2
P2 = P1V1/V2
P2= 101325 × 400/125
P2= 324.24 kPa
Answer:
0.50 mol
Explanation:
The half-life is <em>the time required for the amount of a radioactive isotope to decay to half that amount</em>.
Initially, there are 8.0 moles.
- After 1 half-life, there remain 1/2 × 8.0 mol = 4.0 mol.
- After 2 half-lives, there remain 1/2 × 4.0 mol = 2.0 mol.
- After 3 half-lives, there remain 1/2 × 2.0 mol = 1.0 mol.
- After 4 half-lives, there remain 1/2 × 1.0 mol = 0.50 mol.
Listed below are the inter-molecular bonding that exists in the compound <span>ch3ch2ch2ch2ch2ch2oh.
1. Hydrogen Bonding- The type of bonding that exist between O-H in the compound.
2. Dipole-Dipole Bonding- The type of Bonding that is created when the electronegative draws more electron to its self. Exists between C-O
3. London Dispersion- Created between C-H bonding.</span>