A monosaccharide that consists of 5 carbon atoms, one of which is in a ketone group, is classified as a(n) ketopentose.
Ketone family
The suffix "-one" is added after locating the carbonyl group and, if necessary, designating it with a location number. Ketones are given their common names by first identifying the alkyl groups linked to the carbonyl (in alphabetical order), followed by the prefix "ketone." Several Regular Ketones. The three most significant ketones in terms of scale are acetone, methyl ethyl ketone, and cyclohexanone. Though less frequently than in general organic chemistry, they are still widespread in biochemistry. The simplest ketone is dimethyl ketone, or CH3COCH3, often known as acetone.
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8.3 × 106 - trust me, it's actually right. You can use the calculator to see if I'm correct. Punch in <span>8.3 × 106 = 6.6</span>
Answer:
Reaction will proceed towards forward direction.
Explanation:
Balanced reaction: 
Reaction quotient (
) for this reaction is represented as:
![Q_{c}=\frac{[COCl_{2}]}{[CO][Cl_{2}]}](https://tex.z-dn.net/?f=Q_%7Bc%7D%3D%5Cfrac%7B%5BCOCl_%7B2%7D%5D%7D%7B%5BCO%5D%5BCl_%7B2%7D%5D%7D)
Here, [CO] = [
] = 0.010 M and [
] = 0.070 M
So, 
= 700
As > 
therefore reaction will proceed towards forward direction i.e. more will be produced.
Answer:
P₂ = 261 KPa
Explanation:
Given data:
Volume of sample = 200 mL
Initial pressure = 110 KPa
Initial temperature = 275 K
Final volume = 95 mL
Final temperature = 310 K
Final pressure = ?
Solution:
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₂ = P₁V₁T₂ /T₁ V₂
P₂ = 110 KPa× 200 mL× 310 K /275 K × 95 mL
P₂ = 6820000 KPa / 26125
P₂ = 261 KPa
Answer:
Moles = Molecules / (6.0221415 x 10^23)
Explanation:
