- The chemical symbol of the isotope boron-11 is ¹¹B.
- The atomic mass of the isotope boron-11 is equal to 11.009306.
- The abundance in nature of the isotope boron-11 is equal to 80.1%.
<h3>What is an isotope?</h3>
An isotope can be defined as the atom of a chemical element that has the same number of protons but different number of neutrons. This ultimately implies that, the isotopes of an element have the same atomic number (number of protons) but different atomic mass (number of neutrons).
In Chemistry, there are two main isotopes of boron and these include the following:
Boron-11 is the most stable isotope of boron and it is characterized by the following:
- The chemical symbol of the isotope boron-11 is ¹¹B.
- The atomic mass of the isotope boron-11 is equal to 11.009306.
- The abundance in nature of the isotope boron-11 is equal to 80.1%.
Read more on Boron-11 here: brainly.com/question/6283234
#SPJ1
Answer: pH = 14
Explanation: Please see the attachments below
Answer:
8.37 grams
Explanation:
The balanced chemical equation is:
C₆H₁₂O₆ ⇒ 2 C₂H₅OH (l) + 2 CO₂ (g)
Now we are asked to calculate the mass of glucose required to produce 2.25 L CO₂ at 1atm and 295 K.
From the ideal gas law we can determine the number of moles that the 2.25 L represent.
From there we will use the stoichiometry of the reaction to determine the moles of glucose which knowing the molar mass can be converted to mass.
PV = nRT ⇒ n = PV/RT
n= 1 atm x 2.25 L / ( 0.08205 Latm/kmol x 295 K ) =0.093 mol CO₂
Moles glucose required:
0.093 mol CO₂ x ( 1 mol C₆H₁₂O₆ / 2 mol CO₂ ) = 0.046 mol C₆H₁₂O₆
The molar mass of glucose is 180.16 g/mol, then the mass required is
0.046 mol x 180.16 g/mol = 8.37 g
<span>the formation of a gas
</span>
