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Lilit [14]
4 years ago
7

Factor the following polynomial by grouping.

Mathematics
2 answers:
Olenka [21]4 years ago
5 0
Since all four terms don't have a common factor we will group them in pairs with common factors.
6uv - 3v^3 + 4u - 2v^2
6uv + 4u - 3v^3 - 2v^2
Take out 2u from the first two terms and -v^2 from the last two terms. The goal is to have a common factor once we take out the GCF's.
2u( 3v + 2) - v^2(3v + 2)
Now we have two terms:
[2u(3v+2)] + [-v^2(3v+2)]
These two terms have a GCF of (3v + 2). Take that out:
(3v + 2)(2u - v^2)
Studentka2010 [4]4 years ago
5 0
6uv-3v^3+4u-2v^2
=3v (2u-v^2)+2 (2u-v^2)
=(3v+2)(2u-v^2)
option A)


(x^2 means x raised to the power of two)


HOPE IT HELPS!!!!☺☺
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Let theta be an angle in quadrant II such that cos theta = -2/3
Iteru [2.4K]

Answer:

So we have \csc(\theta)=\frac{3 \sqrt{5}}{5} \text{ and } \tan(\theta)=\frac{-\sqrt{5}}{2}.

Step-by-step explanation:

Ok so we are in quadrant 2, that means sine is positive while cosine is negative.

We are given \cos(\theta)=\frac{-2}{3}(\frac{\text{adjacent}}{\text{hypotenuse}}).

So to find the opposite we will just use the Pythagorean Theorem.

a^2+b^2=c^2

(2)^2+b^2=(3)^2

4+b^2=9

b^2=5

b=\sqrt{5}  This is the opposite side.

Now to find \csc(\theta) and \tan(\theta).

\csc(\theta)=\frac{\text{hypotenuse}}{\text{opposite}}=\frac{3}{\sqrt{5}}.

Some teachers do not like the radical on bottom so we will rationalize the denominator by multiplying the numerator and denominator by sqrt(5).

So \csc(\theta)=\frac{3}{\sqrt{5}} \cdot \frac{\sqrt{5}}{\sqrt{5}}=\frac{3 \sqrt{5}}{5}.

And now \tan(\theta)=\frac{\text{opposite}}{\text{adjacent}}=\frac{\sqrt{5}}{-2}=\frac{-\sqrt{5}}{2}.

So we have \csc(\theta)=\frac{3 \sqrt{5}}{5} \text{ and } \tan(\theta)=\frac{-\sqrt{5}}{2}.

7 0
3 years ago
Read 2 more answers
An investigator claims, with 95 percent confidence, that the interval between 10 and 16 miles includes the mean commute distance
RideAnS [48]

Answer:

Hello the options to your question is missing below are the options

 A) if sample means were obtained for a long series of samples, approximately 95 percent of all sample means would be between 10 and 16 miles

B.the unknown population mean is definitely between 10 and 16 miles

C.if these intervals were constructed for a long series of samples, approximately 95 percent would include the unknown mean commute distance for all Californians

D.the unknown population mean is between 10 and 16 miles with probability .95

Answer : if these intervals were constructed for a long series of samples, approximately 95 percent would include the unknown mean commute distance for all Californians  ( c )

Step-by-step explanation:

95%  confidence

interval = 10 to 16 miles

To have 95% confidence signifies that if these intervals were constructed for a long series of samples, approximately 95 percent would include the unknown mean commute distance for all Californians

confidence interval covers a range of samples/values in the interval and the higher the % of the confidence interval the more precise the interval is,

7 0
3 years ago
Please help with this problem
fenix001 [56]

Answer:

y⁷/x⁵ , I hope this helps

4 0
3 years ago
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8 0
3 years ago
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I'm having trouble understanding this word problem and how they got 6x=44+2x from it.
jenyasd209 [6]
Ok well since it says the product of a number and 6 is 44 more than twice the number.  and from this they got 6x=44+2x because it SAYS THE PRODUCT OF A NUMBER U DON'T KKNOW WHAT THE NUMBER IS SO U USE A VARIABLE WHICH IS 6X THEY GOT = 44 FROM THE PRODUCT AND 2X FROM MORE THAN TWICE THE NUMBER AND TWICE IS 2 AND U DON'T KNOW WHAT THE NUMBER IS SO ONCE AGAIN USE A VARIABLE  
                   
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5 0
3 years ago
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