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Rainbow [258]
3 years ago
5

PLEASE HELP ITS DUE TMR N I JUST NEED A ANSWER

Mathematics
1 answer:
Daniel [21]3 years ago
7 0

The second answer because addition is commutative.


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Write an equation of the line in point-slope form that passes through the given points (-3,2) (5,5)
daser333 [38]
I think it is: y=0.375x+3.125

a=(5-2)/(5- -3)=3/8=0.375

Find b

(5)=0.375(5)+b
(5)=1.875+b
5-1.875=b
b=3.125
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PLEASE NO LINKS I LOST SO MANY POINTS
Ann [662]

Answer:

We will split the trapezoid into right angle triangle and rectangle

Traingle with base 3cm and height 10 - 6 = 4cm

Area of traingle

       = \frac{1}{2}*base *height = \frac{1}{2} * 3 * 4 = 6cm^{2}

Area of rectangle with sides 6cm and 3cm

       =6 * 3 = 18cm^{2}

Therefore, area of the trapezoid

       = 6+18 = 24cm^{2}

Area of the semi circle with radius 3/2 = 1.5cm

        = \frac{1}{2}\pi r^{2}  = \frac{1*\pi *1.5*1.5}{2} = 1.125\pi cm^{2}

Total area = 24 + 1.125\pi =27.53cm^{2}

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3 years ago
For a certain model of car the distance d required to stop the vehicle if it is traveling at v mi/h is given by the formula d =
enyata [817]
Given that <span>For a certain model of car the distance d required to stop the vehicle if it is traveling at v mi/h is given by the formula d=v+\frac{v^2}{20}, where [tex]d is measured in feet.

If Kerry wants her stopping distance not to exceed 75 ft, then the range of speeds (in mi/h) can she travel is obtained as follows:

v+ \frac{v^2}{20} \leq75 \\  \\ 20v+v^2\leq1,500 \\  \\ v^2+20v+100\leq1,500+100 \\  \\ (v+10)^2\leq1,600 \\  \\ |v+10|\leq\sqrt{1,600} \\  \\ -40\leq v+10\leq40 \\  \\ -40-10\leqv\leq v\leq40-10 \\  \\ -50\leq v\leq30

Therefore, the range of speed she can travel is v\leq30\ mi/hr
</span>
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What is the slope of the line represented by the equation y = y equals 4 Over 5
OLEGan [10]

\bf y= \stackrel{\stackrel{m}{\downarrow }}{\cfrac{4}{5}}x-3\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

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