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Answer:
6 dm
Step-by-step explanation:
Triangle DBE is similar to triangle ABC, so their side lengths are proportional.
DE/AC = DB/AB
The length of DB can be found from ...
DB +AD = AB
DB = AB -AD = (15 -10) dm = 5 dm
So, we can fill in the proportion:
DE/(18 dm) = (5 dm)/(15 dm)
DE = (18 dm)·(1/3) . . . . . . . . . . simplify, multiply by 18 dm
DE = 6 dm
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Answer:
(1) The possible outcomes are: X = {0, 1, 2, 3}.
(2) The number of times should Hartley spin a difference of 1 is 36.
(3) The number of times should Hartley spin a difference of 0 is 24.
Step-by-step explanation:
The number of sections on the spinner is 4 labelled as {1, 2, 3, 4}.
The total number of spins for each of the spinner is, <em>n</em> = 96.
(1)
The sample space of spinning both the spinners together are:
S = {(1, 1), (1, 2), (1, 3), (1, 4)
(2, 1), (2, 2), (2, 3), (2, 4)
(3, 1), (3, 2), (3, 3), (3, 4)
(4, 1), (4, 2), (4, 3), (4, 4)}
Total = 16.
The possible outcomes are:
X = {0, 1, 2, 3}.
(2)
The sample space with the difference 1 are:
S₁ = {(1, 2), (2, 1), (2, 3), (3, 2), (3, 4), (4, 3)}
n (S₁) = 6
The probability of the difference 1 is:
The spinners were spinner 96 times.
The expected number of times would Hartley spin a difference of 1 is:
Thus, the number of times should Hartley spin a difference of 1 is 36.
(3)
The sample space with the difference 0 are:
S₂ = {(1, 1), (2, 2), (3, 3), (4, 4)}
n (S₂) = 4
The probability of the difference 0 is:
The spinners were spinner 96 times.
The expected number of times would Hartley spin a difference of 0 is:
Thus, the number of times should Hartley spin a difference of 0 is 24.