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3 years ago

a rectangle is 4 times as long as it wide. if the length is increased by 4 inches and the width is decreased by 1 inch, the area

will be 60 square inches. what were the dimensions of the original rectangle. and please help me

Mathematics

1 answer:

Mekhanik [1.2K]3 years ago

6 0

$x-\ width\\
y-\ length\\
4x=y\\
(y+4)(x-1)=60\\
(4x+4)(x-1)=60\\
4x^2-4x+4x+4=60\ \ | subtract\ 4\\
4x^2=56\ \ | divide\ by\ 4\\
x^2=14\\
x=\sqrt{14}\\
y=4\sqrt{14}\\\\
Dimensions:\ width=\sqrt{14}in,\ length=4\sqrt{14}in.$

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Step-by-step explanation:

I. Determination of m

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2 ∆ − 5 = √m

2² − 2(2 × –5) + (–5)² = √m

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(n+1) ∆ y = n² + 2n – 2ny – 2y + y² + 1

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2. Then, you need to find the median, or the middle number.

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