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Alinara [238K]
3 years ago
9

What are the 1st 5 terms in this sequance? t_n=2t_(n-1)+t_(n-2) where t1=3, t2=4, and n is a natural number greater than or equa

l to 3.
Mathematics
1 answer:
Zepler [3.9K]3 years ago
3 0
The first two terms are given, t_1=3 and t_2=4.

The third term, according to the formula, is

t_3=2\times4+3=11

and the next two terms are

t_4=2\times11+4=26
t_5=2\times26+11=63
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You need to type the same equation that’s shown above of the text box. If there’s still a technical issue, let me know, and I’ll try to help!
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2 years ago
Suppose that a local trout population exhibits exponential growth by doubling every 4 years. Considering that the initial popula
antoniya [11.8K]
Okay, so this is just a basic multiplication problem. first, we need to divide to figure out how much the trout population grows after 1 year. If it doubles in 4 years, then it will rise by a quarter each single year. So to put that in terms of fractions, then for every year, the equation would be 250x1/4. So then we do the equation, coming up with 62.5. This means that the population rises roughly 63 fish a year. So after 1 year, you will have roughly 313 fish. (312.5 to be exact). Then to get that by ten years, we can just multiply the number that we got for one year by ten. 62.5x10=625. So then we add the 250 original trout, and 250+625=875. So after 10 years, there will be 875 trout.
8 0
3 years ago
The table below represents the displacement of a horse from its barn as a function of time:
taurus [48]

"Part A: What is the y-intercept of the function, and what does this tell you about the horse? (4 points)" The y-intercept is (0,8), which tells us that at the beginning the horse is 8 miles from the barn.


"Part B: Calculate the average rate of change of the function represented by the table between x = 1 to x = 3 hours, and tell what the average rate represents. (4 points)" The value of the function at x=1 is 58 and that at x=3 is 158. Thus, the change in the horse's distance from the barn is 158-58, or 100 feet. The time period involved here is 2 sec. Thus, the average rate of change of the horse's position with respect to time is


100 feet

average rate of change = ---------------- = 50 ft/sec

2 sec


If the horse were to move steadily at a fixed rate from 58 feet to 158 feet from the barn, its average rate would be 50 ft/sec.


"Part C: What would be the domain of the function if the horse continued to walk at this rate until it traveled 508 feet from the barn? (2 points)"


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7 0
3 years ago
A total of 729 students participate in a school pep rally event. If every 30 minutes, 2/3 of the students leave, after 2 hours,
trapecia [35]

There will be 9 students left at the prep rally after 2 hours.

After 30 minutes

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  • 2/3 of 729 = 486
  • Number of students left = 729 - 486 = 243

After 1 hour:

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  • Number of students left = 243 - 162 = 81

After 1 hour 30 minutes :

  • 2/3 of 81 = 54
  • Number of students left = 81 - 54 = 27

After 2 hours :

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Therefore, the Number of students left after 2 hours will be 9.

Learn more : brainly.com/question/18112348

5 0
3 years ago
If I've gained 35 pounds in 186 days, how many pounds per day?
Dmitriy789 [7]

Answer:

.188 pounds per day

Step-by-step explanation:

Given

  • 35 pounds gained in 186 days

<u>Divide the amount of pounds gained by the total number of days</u>

35/186 = .188

<u>Answer</u>

Approximately .188 pounds per day.

6 0
3 years ago
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