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2 years ago

13

Solve for x (no need to explain but it would be best if you would because this is gonna be in my staar)

1 answer:

erastovalidia [21]2 years ago

8 0

Answer:

x=1

Step-by-step explanation:

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You deposit $2700 in an account that earns simple interest. After 12 months, the account earns $64.80 in interest, what is the a

Masja [62]

Answer:$4449.6.

Step-by-step explanation:

You deposit $2700 into a bank account paying 64.8% simple interest per year. You left the money in for 1 year. Find the interest earned and the amount at the end of those 1 year?

Result:

The interest is $1749.6 and the amount is $4449.6.

Explanation:

STEP 1: Find an interest by using the formula , where I is interest, P is total principal, i is rate of interest per year, and t is total time in years.

In this examplee P = $2700, i = 64.8% and t = 1 years, so

STEP 2: Find an amount by using the formula .A =P+I

Since P = $2700 and I = $1749.6 we have

5 0

2 years ago

What is the area?<br> 7 m<br> 4 m<br> square meters?

bija089 [108]

Answer:

28 square meters

Step-by-step explanation:

7 x 4= 28

28 square meters

3 0

3 years ago

What is 5/11 in decimal form? (round your answer to the nearest hundredth.)?

natita [175]

5/11 in decimal form is .45

4 0

2 years ago

Write a recursive formula and an explicit formula for the following arithmetic sequence

Mekhanik [1.2K]

Ummmmm add 4? The difference between each number is the same

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2 years ago

A hoop, a uniform solid cylinder, a spherical shell, and a uniform solid sphere are released from rest at the top of an incline.

Serjik [45]

Answer:

Step-by-step explanation:

Given

Hoop, Uniform Solid Cylinder, Spherical shell and a uniform Solid sphere released from Rest from same height

Suppose they have same mass and radius

time Period is given by

$t=\sqrt{\frac{2h}{a}}$ ,where h=height of release

a=acceleration

$a=\frac{g\sin \theta }{1+\frac{I}{mr^2}}$

Where I=moment of inertia

a for hoop

$a=\frac{g\sin \theta }{1+\frac{mr^2}{mr^2}}$

$a=\frac{g\sin \theta }{2}$

a for Uniform solid cylinder

$a=\frac{g\sin \theta }{1+\frac{mr^2}{2mr^2}}$

$a=\frac{2g\sin \theta }{3}$

a for spherical shell

$a=\frac{g\sin \theta }{1+\frac{2mr^2}{3mr^2}}$

$a=\frac{3g\sin \theta }{5}$

a for Uniform Solid

$a=\frac{g\sin \theta }{1+\frac{2mr^2}{5mr^2}}$

$a=\frac{5g\sin \theta }{7}$

time taken will be inversely proportional to the square root of acceleration

$t_1=k\sqrt{2}=1.414k$

$t_2=k\sqrt{\frac{3}{2}}=1.224k$

$t_3=k\sqrt{\frac{5}{3}}=1.2909k$

$t_4=k\sqrt{\frac{7}{5}}=1.183k$

thus first one to reach is Solid Sphere

second is Uniform solid cylinder

third is Spherical Shell

Fourth is hoop

3 0

3 years ago