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Nonamiya [84]
4 years ago
15

What are the elements in the "dip" of the periodic table called?

Chemistry
1 answer:
pogonyaev4 years ago
3 0

Answer:

Transition metals are the elements

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Which of the following atoms has the largest atomic radius? Provide an explanation
trapecia [35]

Answer:

d Rubidium

Explanation:

The atomic radius of an atom is the distance from the center of the nucleus to its outermost electron.

The atomic radius of elements varies in the periodic table, it increases as you go down in a group and decreases along the period from left to right.  

All the elements listed: Hydrogen, Sodium, Lithium and Rubidium belong to the same group in the periodic table (group 1), Since atomic radius increases from top to bottom in a group, Rubidium has the largest atomic radius.

4 0
3 years ago
Calculate the number of grams of solid aluminium chloride that will form when a mixture containing 0.150 g of aluminum powder an
Alinara [238K]

Answer:

the answer is B:) have a good day

5 0
4 years ago
A gas occupies 3.8 L at -18° C and 975. torr. What volume would this gas occupy at STP?
Aleks04 [339]

To solve the question we will assume that the gas behaves like an ideal gas, that is to say, that there is no interaction between the molecules. Assuming ideal gas we can apply the following equation:

PV=nRT

Where,

P is the pressure of the gas

V is the volume of the gas

n is the number of moles

R is a constant

T is the temperature

Now, we have two states, an initial state, and a final state. The conditions for each state will be.

Initial state (1)

P1=975Torr=1.28atm

V1=3.8L

T1=-18°C=255.15K

Final state(2), STP conditions

P2=1atm

T2=273.15K

V2=?

We will assume that the number of moles remains constant, so the nR term of the first equation will be constant. For each state, we will have:

\begin{gathered} \frac{P_1V_1}{T_1}=nR \\ \frac{P_2V_2}{T_2}=nR \end{gathered}

Since nR is the same for both states, we can equate the equations and solve for V2:

\begin{gathered} \frac{P_{2}V_{2}}{T_{2}}=\frac{P_1V_1}{T_1} \\ V_2=\frac{P_{1}V_{1}}{T_{1}}\times\frac{T_2}{P_2} \end{gathered}

We replace the known values:

V_2=\frac{1.28atm\times3.8L}{255.15K}\times\frac{273.15K}{1atm}=5.2L

At STP conditions the gas would occupy 5.2L. First option

8 0
1 year ago
How many molecules of CH4 are in 24.1 g of this compound?
jok3333 [9.3K]

<u>1) find molar mass of CH₄</u>

=12.01+4(1.01)\\\\=16.05\ g/mol

<u>2) determine moles of CH₄</u>

=24.1g\ CH_{4}\ x\ \frac{1\ mol\ CH_{4}}{16.05g\ CH_{4}}\\\\=1.501557632\ mol\ CH_{4}

<u>3) multiply by avogadro's number</u>

=1.501557632\ mol\ CH_{4}\ x\ \frac{6.022\ x\ 10^{23}\ molecules\ CH_{4}}{1\ mol\ CH_{4}} \\\\=9.04238006\ x\ 10^{23}\\\\=9.04\ x\ 10^{23}\ molecules\ CH_{4}

7 0
2 years ago
What element is least metallic<br><br> A zinc<br> B iron<br> C cadmium<br> D silver
Alina [70]
C hope this helps. Please say thank you if u can
8 0
3 years ago
Read 2 more answers
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