Electrolysis hydrocloric acid and both of the electrode uses a platinium electrode... what will happen to both of the electrode?
1 answer:
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Answer:
2.86mol/L
Explanation:
Given parameters:
Number of moles of MgCl₂ = 7.15moles
Volume of solution = 2.50L
Unknown:
Molarity of the MgCl₂ solution = ?
Solution:
The molarity of a solution is the number of moles of solute found in a given volume.
Molarity =
Insert the parameters and solve;
Molarity = = 2.86mol/L