Question

Three consecutive odd integers have a sum of 33. Find the integers.

Answer 1

They are consecutive *odd* integers. So,

if the first integer is a,
then the second one is a+2
and the third one is a+4.

And we know that
a + a+2 + a+4 = 33

We can find what a is, and that is the smallest number. Then to find the other two, just count up from a.

a + a+2 + a+4 = 33
3a + 6 = 33
a = (33-6)/3 = 9
So the integers are 9, 11, and 13.

Indeed, 9+11+13=33