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Margaret [11]
3 years ago
8

Four dozen bagels cost $30.00.How much change will you recive if you pay for a dozen bagels with a ten dollar bill

Mathematics
1 answer:
nata0808 [166]3 years ago
8 0
4 dozen bagels cost $30

If we divide $30 by 4 we get 7.50 .

7.50 is the price of one dozen bagels.

You pay with a 10 dollar bill.

10 (dollars) - 7.50 (price of one dozen) = 2.50

You will receive $2.50 in change.

Hope I was able to help! :)

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$690.86

Step-by-step explanation:

100% from the original cost is: 2 x 863.57 = $1,727.14

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2 years ago
8v-3v-3+7v simplified
Licemer1 [7]

Your answer is <u>12v-3.</u>

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Steps:

1. Group Like Terms. (8v-3v+7v-3)

2. Add Similar Elements. (8v-3v+7v=12v)

3. Finished. (=12v-3)

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Hope this helped :)

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2 years ago
Rachel types 162 words in 3 minutes. Rachel types at a constant rate.
Mazyrski [523]

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8 0
3 years ago
Let the random variable X be the number of rooms in a randomly chosen owner-occupied housing unit in a certain city. The distrib
natali 33 [55]

Answer:

a) X is a discrete random variable.

b) 2% probability of choosing a unit with 10 rooms

c) 98% probability that a unit chosen at random is not a 10-room unit

d) 30% probability that a unit chosen at random has less than five rooms

e) 7% probability that a unit chosen at random has less than five rooms

Step-by-step explanation:

The distribution means that:

7% probability that a randomly chosen owner-occupied housing unit in a certain city has 3 rooms.

23% probability that a randomly chosen owner-occupied housing unit in a certain city has 4 rooms.

36% probability that a randomly chosen owner-occupied housing unit in a certain city has 5 rooms.

19% probability that a randomly chosen owner-occupied housing unit in a certain city has 6 rooms.

5% probability that a randomly chosen owner-occupied housing unit in a certain city has 7 rooms.

5% probability that a randomly chosen owner-occupied housing unit in a certain city has 8 rooms.

3% probability that a randomly chosen owner-occupied housing unit in a certain city has 9 rooms.

?% probability that a randomly chosen owner-occupied housing unit in a certain city has 10 rooms.

(a) Is X a discrete or continuous random variable?

X is the number of rooms in a randomly selected house. The number of rooms is a countable variable, that is, only assumes values like 1,2,3,4,... You cannot have 3.5 rooms, for example.

So X is a discrete random variable.

(b) What must be the probability of choosing a unit with 10 rooms?

The sum of all probabilities must be 100%(1 decimal). So

0.07 + 0.23 + 0.36 + 0.19 + 0.05 + 0.05 + 0.03 + ? = 1

0.98 + ? = 1

? = 0.02

2% probability of choosing a unit with 10 rooms

(c) What is the probability that a unit chosen at random is not a 10-room unit?

0.07 + 0.23 + 0.36 + 0.19 + 0.05 + 0.05 + 0.03 = 0.98

98% probability that a unit chosen at random is not a 10-room unit

(d) What is the probability that a unit chosen at random has less than five rooms?

7% probability it has 3 rooms

23% probability it has 4 rooms. So

7+23 = 30% probability that a unit chosen at random has less than five rooms

(e) What is the probability that a unit chosen at random has three rooms?

7% probability that a randomly chosen owner-occupied housing unit in a certain city has 3 rooms. So

7% probability that a unit chosen at random has less than five rooms

8 0
3 years ago
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