I need to know what X y and z is

Mathematics

1 answer:

Olenka [21]3 years ago

4 0

You have 3 right-angled triangles so you apply the Pythagoras theorem

z^2 = 4^2 + y^2......(1)

x^2 = 6^2 + y^2 .....(2) Also taking the large triangle:-

x^2 + z^2 = 10^2.......(3)

Subtracting equation (1) from equation 2:-

x^2 - z^2 = 20 .......(4)

Adding (3) + (4):-

2x^2 = 120
x^2 = 60
x = sqrt 60

So , using equation (4) z^2 = x^2 - 20 = 60 - 20 = 40

z = sqrt 40

now we can find y by substituting in equation (1)

y^2 = z^2 - 4^2 = 40 - 16 = 24

y = sqrt 24

You might be interested in

What is 5+x^2=2x^2+13?

pshichka [43]

Take the root of both sides, and solve.

x = 2i sqrt 2, -2i sqrt 2.

4 0

3 years ago

Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be

Oksana_A [137]

<h2>Hello!</h2>

The answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

To calculate the speed of the cars, we need to write two equations, one for each car, in order to create a relation between the two speeds and be able to calculate one in function of the other.

So,

Tet be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

$x_{FirstCar}=x_o+v*t$

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

$x_{SecondCar}=x_o+(v+14mph)*t$

Now, from the statement that both cars met after 2 hours and 45 minutes, and the distance between to cover (between A and B) is 264 miles, so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

$RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph$