For part a: you just need to find how far the vertex has been moved from the origin, or the point (0,0). As the vertex is at the point (2,-3), it has been translated right 2 horizontally and down 3 vertically.
For part b: you use the info found in part a to create the equation in the form of y=A(x-h)^2+k. In this case, A =1, so you can ignore it. The h value is the horizontal distance the vertex has been moved. Since it has been moved right 2, this part of the equation would be (x-2). I know it seems like it should be plus 2, but values in parentheses come out opposite. For the k value, find the vertical shift, which is down3, or -3.
Now that you have h and k, substitute them back into the equation.
Your final answer for part b is: y=(x-2)^2 -3.
Answer:(1,23)(2,21)(4,17)(6,13)
Step-by-step explanation:
Plug in the x values in the graph to the function. For example plug in 2 to it and you get 25-2(2) which transfers to 25-4. 25-4 equals 21
I don’t know pay attention in class and I’m not being mean JK it’s 2,251,926
Find the z-scores for the two scores in the given interval.

For the score x =391,

.
For the score x = 486,

Now you want the area (proportion of data) under the normal distribution from z = -1 to z = 0. The Empirical Rule says that 68% of the data falls between z = -1 to z = 1. But the curve is symmetrical around the vertical axis at z = 0, so the answer you want is HALF of 68%.
Answer:
7.5 square units
Step-by-step explanation:
Base of the triangle = 5 units
Height of the triangle = 3 units
Area of the triangle
