Given the figure of a regular pyramid
The base of the pyramid is a hexagon with a side length = 6
The lateral area is 6 times the area of one of the side triangles
So, the side triangle has a base = 6
The height will be:
![\begin{gathered} h^2=6^2+(\frac{\sqrt[]{3}}{2}\cdot6)^2=36+27=63 \\ h=\sqrt[]{63} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20h%5E2%3D6%5E2%2B%28%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D%5Ccdot6%29%5E2%3D36%2B27%3D63%20%5C%5C%20h%3D%5Csqrt%5B%5D%7B63%7D%20%5Cend%7Bgathered%7D)
so, the lateral area =
blue marbles
y = yellow marbles
Sum = b+y
The <span>chance of a blue marble being drawn first is:
b / (b+y) = 0.55
</span>The <span>chance of a blue marble being drawn first then a yellow next is:
</span>b / (b+y) * y / (b+y-1) = 0.37
This can be solve easily by using a theorem of Bayes
0.37/0.55 = .67 or 67%
Answer:
g =-2
h = 2
Step-by-step explanation:
left end middle right end
G(g,4) (-2,3) (-2,h)
-24e^5/6e = -<span>4e^4
hope it helps</span>
Answer:
20
Step-by-step explanation:
The answer would be 20 due to the fact that it would have to be 50 divided by 2.5 to get the answer of how many steps and 50 divided by 2.5 would equal 20