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slamgirl [31]
3 years ago
5

What is 3(u+1)+4u+1?

Mathematics
1 answer:
il63 [147K]3 years ago
6 0
I’m pretty sure the answer is 7u+4
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The x and y intercepts
ale4655 [162]
Y inter (0, -3) x inter (2,0)
4 0
3 years ago
Need Help Badly<br>What is the solution
Kamila [148]
Sqrt(1-3x)=x+3
[sqrt(1-3x)]^2=(x+3)^2
1-3x=(x+3)(x+3)
1-3x=x^2+6x+9
-3x=x^2+6x+8
0=x^2+9x+8

The answers are -1 and -8 BUT, we have to plug them back into the original equation to make sure we don't get a negative under the square root sign.

After doing this, we realize that only -1 works, so the answer is x=-1

Sorry that this took forever to answer. I was thinking of a good way to explain this, and if you need any further explanation, message me:)

Best wishes:)


5 0
3 years ago
The graph shows a reflection in the x-axis. The matrix M such that, for any point (x, y), M(x, y) = (x', y') is
Rashid [163]

Answer:

This is a reflection about the x-axis.


Step-by-step explanation:

A reflection about the x-axis has the rule

[x,y]-> [x,-y].

Therefore

M[x,y] = [x,-y}

Let M=

|a  b|

|c  d|

Then the matrix multiplication gives

ax+by=x.............(1)

cx+dy=-y............(2)

Solving the previous equations (1) and (2) gives

a=1, b=0

c=0, d=-1

giving M as

|1  0|

|0 -1|


4 0
3 years ago
A town has a population of 8000 and grows at 3% every year. To the nearest tenth of a year, how long will it be until the popula
Alexxx [7]

Answer:

It will take approximately 34 years

Step-by-step explanation:

If a town population is 8000 and grows 3% annually.

How long will it take to reach 16300

growth is 16300 - 8000 = 8300

using simple interest formula

SI = (P × r × t)/100

8300 = (8000 × 3 × t)100

8300= (80 × 3)t

8300 = 240t

t = 8300/240

t ≈ 34 years to the nearest tenth

8 0
3 years ago
Solve the following equation<br> (7X3+4X2+3X+2) + (2X2+X+5)=
rjkz [21]
The way it's written it's 
Simplify the following:
7 X^3 + 4 X^2 + 2 X^2 + 3 X + X + 2 + 5
Grouping like terms, 7 X^3 + 4 X^2 + 2 X^2 + 3 X + X + 2 + 5 = 7 X^3 + (4 X^2 + 2 X^2) + (3 X + X) + (2 + 5):7 X^3 + (4 X^2 + 2 X^2) + (3 X + X) + (2 + 5)
4 X^2 + 2 X^2 = 6 X^2:
7 X^3 + 6 X^2 + (3 X + X) + (2 + 5)
3 X + X = 4 X:
7 X^3 + 6 X^2 + 4 X + (2 + 5)
2 + 5 = 7:Answer:  7 X^3 + 6 X^2 + 4 X + 7
5 0
3 years ago
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