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3 years ago

What is the reason for statement 3 in this proof?

Mathematics

2 answers:

Lapatulllka [165]3 years ago

6 0

Answer: A

Step-by-step explanation:

allsm [11]3 years ago

3 0

The answer is definitely A<span />

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Write in simplest form 6 times 2/3

satela [25.4K]

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3 years ago

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If f(x)=ax+b/x and f(1)=1 and f(2)=5, what is the value of A and B?

LUCKY_DIMON [66]

Answer:

$\huge\boxed{a=9 ; b = -8}$

Step-by-step explanation:

$f(x) = \frac{ax+b}{x}$

Putting x = 1

=> $f(1) = \frac{a(1)+b}{1}$

Given that f(1) = 1

=> $1 = a + b$

=> $a+b = 1$ -------------------(1)

Now,

Putting x = 2

=> $f(2) = \frac{a(2)+b}{2}$

Given that f(2) = 5

=> $5 = \frac{2a+b}{2}$

=> $2a+b = 5*2$

=> $2a+b = 10$ ----------------(2)

Subtracting (2) from (1)

$a+b-(2a+b) = 1-10\\a+b-2a-b = -9\\a-2a = -9\\-a = -9\\a = 9$

For b , Put a = 9 in equation (1)

$9+b = 1\\Subtracting \ both \ sides \ by \ 9\\b = 1-9\\b = -8$

5 0

3 years ago

Difference between spoiled and spoiled rotten

Olegator [25]

I assume the difference between the two would be the spoiled person would be perceived that way from an outside view because when they break their phone, lets say, they're granted with a new one such as an iPhone7 when the original was a blackberry. While the spoiled rotten term would be for those who have behavioral issues when things like "No!" are said to them and a tantrum begins.

7 0

3 years ago

8 professors and 11 students are available to serve on committee. (a) How many ways can a committee of four people be selected?

noname [10]

Answer: a) 3876 b) 18480

Step-by-step explanation:

Given , The number of professors = 8

The number of students are available = 11

Total persons = 8+11=19

a) The number of ways to select 4 people = $^{19}C_{4}$

$=\dfrac{19!}{4!(19-4)!}\ \ \ [\because\ ^nC_r=\dfrac{n!}{r!(n-r)!}]\\=\dfrac{19\times18\times17\times16\times15!}{24\times15!}\\=3876$

Hence, the number of ways to select 4 people = 3876.

b) Number of ways to choose 3 professors and 4 students = $^{8}C_{3}\times^{11}C_{4}$

$=\dfrac{8!}{3!(8-3)!}\times\dfrac{11!}{4!(11-4)!}\\\\=56\times330\\\\=18480$

Hence, the numbers of ways to form a committee with 3 professors and 4 students = 18480.

3 0

3 years ago

I need help someone plz help me

Grace [21]

5) -4+(-3) = -7 because you got -4 and then 3 more negatives so you got 7 negatives

6) -3+2= -1 because you got -3 and then 2 positives , now you have only one negative left

7)5+(-3) = 2 because you have 5 pozitives and then 3 negatives happen, now you got only 2 positives remaining...and so on

5 0

3 years ago

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