Let n = 0, 1, 2, 3, 4, 5, 6, 7....
When n = 0 then 0^2 + 0 = 0. n = 1 we have 1^2 + 1 = 2. And when n = 2 we have 2^2 + 2 = 6. When n= 3 we have 3^2 + 3 = 12. When n = 4 we have 4^2 + 4 = 20. When n = 5 we have 5^2 + 5 = 30. When n = 6 = 6^2 + 6 = 42. And finally when n = 7 we have 7^2 + 7 = 56. So at n = 1, 2, ...7, ... Our values are = 2, 6, 12, 20, 30, 42, and 56. It is obvious that n is always an even number. Hence n^2 + n is always an even integer for all positive integers.
When n = -1 we have (-1)^2 - 1 = 0 when n = -2 we have (-2)^2 -2 = 2. When n = -3 we have (-3)^2 - 3 = 6. When n = -4 we have (-4)^2 - 4 = 16 - 4 =12. When n =-5 we have (-5)^2 -5 = 20. When n = -6 we have (-6)^2 - 6 = 30. When n = (-7)^2 - 7 = 42. Hence n^2 + n is always even for all integers
Answer:
We conclude that the 8 % of calls result in a sale.
We conclude that the 5.3% of sales are made to women.
Step-by-step explanation:
We know that 70% of calls arc not completed (the party does not answer or refuses to talk), that 20% result in talking to a woman, and that 10% result in talking to a man. After that point, 30% of the women and 20% of the men actually buy something.
We calculate what percentage of calls result in a sale, and we get:

We conclude that the 8 % of calls result in a sale.
We know that the ratio of women to men talking on the telephone is 2:1.
We calculate a percent of sales are made to women, and we get:

We conclude that the 5.3% of sales are made to women.
Answer:
71%
Step-by-step explanation:
The original price is 200. The dress was sold for 142.
Take the price of the dress divide the original price (142/200) then times 100.
Hmm they're both even numbers so maybe we can start by cutting each number in half.

18 and 48 had 2 as a common factor.
So factoring a 2 out of each number was the same as cutting each number in half. Try to do something similar with the 9 and 24. They each have something in common.
10.,.............................