Help due tomorrow thank you

I need help please helppppppppppppppppppppppp

Marrrta [24]

Given:

A figure of a circle and two secants on the circle from the outside of the circle.

To find:

The measure of angle KLM.

Solution:

According to the intersecting secant theorem, if two secant of a circle intersect each other outside the circle, then the angle formed on the intersection is half of the difference between the intercepted arcs.

Using intersecting secant theorem, we get

$\angle KLM=\dfrac{1}{2}(Arc(JON)-Arc(KM))$

$(3x-4)=\dfrac{1}{2}(271-(x+6))$

$(3x-4)=\dfrac{1}{2}(271-x-6)$

Multiply both sides by 2.

$6x-8=265-x$

Isolate the variable x.

$6x+x=265+8$

$7x=273$

Divide both sides by 7.

$x=\dfrac{273}{7}$

$x=39$

Now,

$\angle KLM=(3x-4)^\circ$

$\angle KLM=(3(39)-4)^\circ$

$\angle KLM=(117-4)^\circ$

$\angle KLM=113^\circ$

Therefore, the measure of angle KLM is 113 degrees.

5 0

3 years ago

The perimeter of a rectangular baking sheet is 58 inches and its area is 201.25 in.2. What are the length and width of the bakin

anzhelika [568]

Answer:

$Length=17.5\ in\\\\Width=11.5\ in$

Step-by-step explanation:

The formula for calculate the Area of a rectangle is:

$A=lw$

Where "l" is the lenght and "w" is the width.

And the formula for calculate the peimeter of a rectangle is:

$P=2l+2w$

Where "l" is the lenght and "w" is the width.

We know that the perimeter of the rectangular baking sheet is 58 inches and its area is 201.25 in². Then:

$A=201.25\ in^2\\\\P=58\ in$

The steps are:

1. Solve for the "l" from the formula $A=lw$ :

$A=lw\\\\l=\frac{A}{w}\\\\\l=\frac{201.25}{w}$

2. Substitute $l=\frac{201.25}{w}$ into the formula $P=2l+2w$ and solve for "w":

$58=2(\frac{201.25}{w})+2w\\\\58=\frac{402.5}{w}+2w\\\\58=\frac{402.5+2w^2}{w}\\\\58w=402.5+2w^2\\\\2w^2-58w+402.5=0$

Applying the Quadratic formula $x=\frac{-b\±\sqrt{b^2-4ac}}{2a}$ , we get:

$x=w=\frac{-(-58)\±\sqrt{(-58)^2-4(2)(402.5)}}{2(2)}\\\\w_1=17.5\\\\w_2=11.5$

3. Substitute $w_1=17.5$ into $l=\frac{201.25}{w}$ :

$l=\frac{201.25}{17.5}=11.5$

4. Substitute $w_2=11.5$ into $l=\frac{201.25}{w}$ :

$l=\frac{201.25}{11.5}=17.5$

Therefore, since the value of the lenght of a rectangle must be greater that the value of the width, we can conclude that the lenght and the width of the rectangular baking sheet are:

$l=17.5\ in\\\\w=11.5\ in$

8 0

3 years ago

Write an equation in point-slope form for the line. (1,3) (0,1) m=4

Anna [14]

Given coordinates (1,3) and (0,1).

In order to find the equation of line, we need to find the slope between given coordinates.

We know slope formula,

m= $\frac{y2-y1}{x2-x1}$

We have (x1,y1) = (1,3) and (x2,y2) = (0,1).

Plugging values of x1,y1,x2 and y2 in slope formula, we get

$m=\frac{1-3}{0-1}$

Simplifying top and bottom of the fraction we got for slope

$m=\frac{-2}{-1}=2$

We got slope m=2.

We are given second point (0,1), where x-coordinate is 0 and y-coordinate is 1.

y-intercept is a point on y-axis, where x=0.

Therefore, y-intercept = 1.

Now, applying slope-intercept form of the linear equation

y=mx+b, where m is the slope and b is y-intercept.

m=2 and b=1.

Plugging values of m and b in slope-intercept form, we get

y=2x+1.

Therefore, point-slope form for the line is y=2x+1.

5 0

3 years ago

(11x^2+5y^2-8xy)+(x^2-7y^2+4x)

CaHeK987 [17]

Answer:

4x2 - 3xy - 9y2

Step-by-step explanation:

7 0

3 years ago

Write in slope-intercept form an equation of the line that passes through the points (−6,−3) and (18,1).

Brilliant_brown [7]

6x-y+33=0

Step-by-step explanation:

m=y2-y1/x1-x2

m=1-(-3)/18-(-6)

m=4/24m=6

m=y-y1/x-x1

6=y-y1/x-x1

6x-y+33=0

4 0

2 years ago