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3 years ago

5

Darren is on a super effective diet. He has lost 16% of his weight this month. If he started with 75 kg, how much does he weigh

now?

2 answers:

Andre45 [30]3 years ago

6 0

Answer:

63 kg

Step-by-step explanation:

Since Darren lost 16% of his weight, this means he weighs

100-16 = 84% of what he used to.

84% = 84/100 = 0.84; this means Darren weighs

0.84(75) = 63 kg

Papessa [141]3 years ago

5 0

16/100=0.16
0.16*75=12
75-12=63

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3 years ago

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b) n = 1026.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

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$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

99% confidence level

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(a) Assume that nothing is known about the percentage to be estimated.

We need to find n when M = 0.04.

We dont know the percentage to be estimated, so we use $\pi = 0.5$ , which is when we are going to need the largest sample size.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 2.575\sqrt{\frac{0.5*0.5}{n}}$

$0.04\sqrt{n} = 2.575*0.5$

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(b) Assume prior studies have shown that about 55% of full-time students earn bachelor's degrees in four years or less.

$\pi = 0.55$

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$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

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$0.04\sqrt{n} = 2.575*\sqrt{0.55*0.45}$

$(\sqrt{n}) = \frac{2.575*\sqrt{0.55*0.45}}{0.04}$

$(\sqrt{n})^{2} = (\frac{2.575*\sqrt{0.55*0.45}}{0.04})^{2}$

$n = 1025.7$

Rounding up

n = 1026.

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3 years ago