The metallurgist must use 5.538 pounds of an alloy with 39 % copper and 42.462 pounds of an alloy with 62 % copper.
<h3>How to calculate proportions of components associated to an alloy</h3>
Herein we must create a new alloy by using correct quantities of two alloys with distinct <em>copper</em> concentrations. All required information can be found by concept of <em>weighted</em> averages:
(62/100) · (48 lb) = (39/100) · x + (65/100) · (48 - x)
62 · 48 = 39 · x + 65 · 48 - 65 · x
3 · 48 = 26 · x
x = 5.538 lb
The metallurgist must use 5.538 pounds of an alloy with 39 % copper and 42.462 pounds of an alloy with 62 % copper.
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Answer:
rounded it is 6.
Step-by-step explanation:
2/3= .67
.67 x 9 = 6.03
round to 6
Answer:
B
Step-by-step explanation:
Take f(x) and plug into g(x)
(2x+1)+14 = 2x+15
F(x) = -2(x - 3)^2 + 2 = -2(x^2 - 6x + 9) + 2 = -2x^2 + 12x - 18 + 2 = -2x^2 + 12x - 16
f(x) = -2x^2 + 12x - 16