The zero of the linear function is -2
<h3>How to determine the zero of the function?</h3>
This is the point where the line of the equation crosses the x-axis
From the attached figure, the line cross the graph at:
x = -2
Hence, the zero of the function is -2
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5x-4-x=4(x+1)
5x-4-x=4(x)+4(1)
(5x-x)-4=4x+4
4x-4=4x+4
+4 +4
4x=4x+8
/4 /4
x = x+2
-x -x
0=2
Answer:
zero
Step-by-step explanation:
Here, we want to get the sign of the expression
since a is zero, it multiplies any value in the brackets to be zero too
zero is neither positive nor negative
What this mean is that we can only explicitly classify the sign as zero
Answer:
by using pythagoras theorem
Point P' would be in the II quadrant; the answer is b
