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romanna [79]
3 years ago
5

Jenna and her mom are addressing envelopes for Jenna's wedding invitations. So far, Jenna has addressed 2/9 of the envelopes, an

d her mom has also addressed 2/9 . What portion of the envelopes have they addressed so far?
15 pts.
Mathematics
2 answers:
frutty [35]3 years ago
5 0
I can’t tell if you want fraction or decimal so ima say 4/9
Nostrana [21]3 years ago
4 0

Answer: 4/9

Step-by-step explanation:

Im guessing just add the two fractions together since they are not telling you how many are all together.

You might be interested in
What is 12+ n means in verbal expression
Mandarinka [93]

the sum of 12 and a number/n

5 0
2 years ago
The base diameter and the height of a cone are both
WITCHER [35]

Answer:

11/ 42. *. X^ 2. * X = I/3 X A * h; if E = 1/3 A

Then the answer is EX

Step-by-step explanation:

Volume of cone= 1/3 * base area * height

= 1/3 * pi* (X/2)^2 * X

= 1/3. * 22/ 7 * X^3/4

= 22/ 21 * X^3 / 4

= 11/21 *. X^2/ 2. *. X

= 11/ 42. * X^3

= 11/ 42. *. X^ 2. * X

3 0
2 years ago
Plz help!! Will give 30 points!!
Inessa [10]

Answer:

B) 12

Step-by-step explanation:

C is the circumference, d is the diameter, and r is the radius.  They are related by the following equations:

d = 2r

C = πd = 2πr

If d = 6.0, then r = 3.0.

If C / C' = 0.25, then:

(2πr) / (2πr') = 0.25

r / r' = 0.25

3 / r' = 0.25

r' = 12

8 0
3 years ago
Read 2 more answers
What is the area or the figure below?
nataly862011 [7]
U have to cross out the 10 then u have those 4 5s 5x5=25 5x5=25 25+25=50.





(My answer might be wrong so wait until other ppl answer. If I got riGhT like my thing -3-)
5 0
3 years ago
Read 2 more answers
The rate at which the temperature is dropping is 6t 5t2 degrees Celsius per hour t hours after sundown. How much had the tempera
Whitepunk [10]

Using a differential equation, it is found that the temperature dropped 72 degrees Celsius between sundown and 3 hours after sundown.

<h3>What is the differential equation that describes the temperature in t hours after sundown?</h3>

The rate at which the temperature is dropping is 6t + 5t^2 degrees Celsius per hour t hours after sundown, hence the <em>differential equation</em> is:

\frac{dT}{dt} = 6t + 5t^2

Applying <em>separation of variables</em>, we find the solution as follows:

\frac{dT}{dt} = 6t + 5t^2

dT = (6t + 5t^2) dt

\int dT = \int (6t + 5t^2) dt

T(t) = \frac{5t^3}{3} + 3t^2 + T(0)

In which T(0) is the temperature at sundown.

In 3 hours, the change will be of:

C = T(3) - T(0) = \frac{5t^3}{3} + 3t^2|_{t = 3}

Hence:

\frac{5(3)^3}{3} + 3(3)^2 = 45 + 27 = 72

The temperature dropped 72 degrees Celsius between sundown and 3 hours after sundown.

You can learn more about differential equations at brainly.com/question/24348029

5 0
2 years ago
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