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Setler [38]
2 years ago
10

What is ( m = 3 and contains (4, -1) in slope intercept form​

Mathematics
2 answers:
AURORKA [14]2 years ago
8 0

<em>Answer:</em>

<em>Y = 3x-13</em>

<em>Step-by-step explanation:</em>

<em>y= mx+b </em>

<em>4 = x  and -1 =y </em>

<em>(4,-1)= (x,y) </em>

<em>m=3= slope </em>

<em>y=mx+b</em>

<em>-1=3(4)+b</em>

<em>-1=12+b</em>

<em>you subtract 12 on both sides </em>

<em>b = -13 </em>

<em>Y = 3x-13</em>

Vikentia [17]2 years ago
4 0

Answer:

y + 1 = 3(x - 4)

Step-by-step explanation:

slope formula is (y - y1) = m (x - x1)

so plug in the information and you get

(y - (-1)) = 3 (x - (4))

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The proportion of students who own a cell phone on college campuses across the country has increased tremendously over the past
galina1969 [7]

Complete Question

The complete question is shown on the uploaded image  

Answer:

1 ) The correct option B

2) The correct option is  C

3)  The correct option is  C

4)  The correct option is  C

Step-by-step explanation:

From the question we are told that

   The proportion that own a cell phone  is  p = 0.90

    The  sample  size is  n =  15

Generally the appropriate distribution for X is mathematically  represented as

      X  \ is  \ B( n , p )

So  

       X  \ is  \ B( 15 , 0.90 )

Generally the number students that  own a cell phone in a simple random sample of 15 students is mathematically represented as

              \mu  =  n  *  p

              \mu  =  15 *  0.90

              \mu  =   13.5

Generally the standard deviation of the number of students who own a cell phone in a simple random sample of 15 students is mathematically represented as

                \sigma  =  \sqrt{ n *  p *  q }

Where  q is mathematically evaluated as

          q =  1- p

           q =  1- 0.90

           q =  0.10

            \sigma  =  \sqrt{ 15 *  0.90 *  0.10 }

            \sigma  = 1.16

Generally the probability that all students in a simple random sample of 15 students own a cell phone is mathematically represented as

   P(X =  15) =  \left 15} \atop {}} \right.C_{15} *  p^{15} *  q^{15 - 15}    

     P(X =  15) =  \left 15} \atop {}} \right.C_{15} *  (0.90)^{15} *  (0.10 )^{15 - 15}

From the combination calculator  is      \left 15} \atop {}} \right.C_{15} =  1

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