Answer:
0.150 < (Proportion of Sandy's pie) < 0.167
15% < (Percentage of Sandy's pie) < 16.7%
Step-by-step explanation:
Total percentage of pie = 100% or 1
George, Sandy, Carlos, and Michelle all ate a piece of the pie.
George ate a fraction of 0.150
Michelle ate a fraction of (1/6) = 0.167
Carlos ate a fraction of (1/7) = 0.143
The amount of pie left = 1 - 0.15 - (1/6) - (1/7) = 0.5405
And Sandy is known to eat more than two of her friends, but less than one of them.
Of the amount of pie eaten by the first 3 friends, (1/6) is the highest proportion.
Hence, it is evident that Sandy ate more than 0.143 and 0.150 (Carlos and George) but less than Michelle (0.167).
So, mathematically, the possible proportion of cake that Sandy ate is
0.150 < (Proportion of Sandy's pie) < 0.167
Hope this Helps!!!
Answer:
Actually, what you said you have so far is not correct. The 2 correct answers are the 1st one (x + y = 15) and the 5th one (15x + 10y > 180)
Step-by-step explanation:
If tutoring French is x hours and scooping ice cream is y hours and he is going to work 15 hours for sure doing both, then we can add them together to get that x hours + y hours = 15 hours, or put simply: x + y = 15.
Now we are going to throw in the added fun of the money he makes doing each. The thing to realize here is that we can only add like terms. So looking at the equation above, we have x hours of tutoring and y hours of scooping, so if we want to add them, we will add those number of hours together to get the total number of hours he worked, which we know to be 15. The same goes for money. If we add money earned from tutoring to money earned from scooping, we need that to be greater than the money he wants to earn which is 180 at least. Because he wants to earn MORE than $180. we use the ">" sign. Since he earns $15 an hour tutoring, that expression is $15x; since he earns $10 an hour scooping, that expression is $10y. Now add them together (and you CAN because they are both expressions relating dollars to dollars) and set the sum > $180:
$15x + $10y > $180. That's why your answer is not correct. Use mine (with the understanding that you care about why yours is wrong and mine is correct) and you'll be fine.
Answer:
a) 0.283 or 28.3%
b) 0.130 or 13%
c) 0.4 or 40%
d) 30.6 mm
Step-by-step explanation:
z-score of a single left atrial diameter value of healthy children can be calculated as:
z=
where
- X is the left atrial diameter value we are looking for its z-score
- M is the mean left atrial diameter of healthy children (26.7 mm)
- s is the standard deviation (4.7 mm)
Then
a) proportion of healthy children who have left atrial diameters less than 24 mm
=P(z<z*) where z* is the z-score of 24 mm
z*=
≈ −0.574
And P(z<−0.574)=0.283
b) proportion of healthy children who have left atrial diameters greater than 32 mm
= P(z>z*) = 1-P(z<z*) where z* is the z-score of 32 mm
z*=
≈ 1.128
1-P(z<1.128)=0.8703=0.130
c) proportion of healthy children have left atrial diameters between 25 and 30 mm
=P(z(25)<z<z(30)) where z(25), z(30) are the z-scores of 25 and 30 mm
z(30)=
≈ 0.702
z(25)=
≈ −0.362
P(z<0.702)=0.7587
P(z<−0.362)=0.3587
Then P(z(25)<z<z(30)) =0.7587 - 0.3587 =0.4
d) to find the value for which only about 20% have a larger left atrial diameter, we assume
P(z>z*)=0.2 or 20% where z* is the z-score of the value we are looking for.
Then P(z<z*)=0.8 and z*=0.84. That is
0.84=
solving this equation for X we get X=30.648
Answer:
-2
Step-by-step explanation:
if x=- 2 then f(x)=(-2-5)3(-2+2)=0
so x=-2 is correct
Answer: ![1-(\frac{364}{365})^n](https://tex.z-dn.net/?f=1-%28%5Cfrac%7B364%7D%7B365%7D%29%5En)
Step-by-step explanation:
Binomial probability formula :-
, where P(x) is the probability of getting success in x trials, n is the total number of trials and p is the probability of getting success in each trial.
We assume that the total number of days in a particular year are 365.
Then , the probability for each employee to have birthday on a certain day :
![p=\dfrac{1}{365}](https://tex.z-dn.net/?f=p%3D%5Cdfrac%7B1%7D%7B365%7D)
Given : The number of employee in the company = n
Then, the probability there is at least one day in a year when nobody has a birthday is given by :-
![P(x\geq1)=1-P(x](https://tex.z-dn.net/?f=P%28x%5Cgeq1%29%3D1-P%28x%3C1%29%5C%5C%5C%5C1-P%280%29%5C%5C%5C%5C%3D1-%28%5EnC_0%28%5Cfrac%7B1%7D%7B365%7D%29%5E0%281-%5Cfrac%7B1%7D%7B365%7D%29%5En%29%5C%5C%5C%5C%3D1-%281%29%28%5Cfrac%7B364%7D%7B365%7D%29%5En%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5B%5Ctext%7Bsince%7D%5C%20%5EnC_0%3D1%5D%5C%5C%5C%5C%3D1-%28%5Cfrac%7B364%7D%7B365%7D%29%5En)
Hence, the probability there is at least one day in a year when nobody has a birthday =![1-(\frac{364}{365})^n](https://tex.z-dn.net/?f=1-%28%5Cfrac%7B364%7D%7B365%7D%29%5En)