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podryga [215]
3 years ago
10

Assuming an efficiency of 41.50%, calculate the actual yield of magnesium nitrate formed from 136.7 g of magnesium and excess co

pper(ii) nitrate.
Chemistry
1 answer:
Sergio [31]3 years ago
5 0
The actual yield is 489.8g of magnesium nitrate
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Mercury(II) oxide (HgO) decomposes to form mercury (Hg) and oxygen (O2). The balanced chemical equation is shown below. 2HgO Rig
yulyashka [42]

15.63 moles of HgO are needed to produce 250. 0 grams of Oxygen.

<h3>How we calculate moles from masses?</h3>

Moles of any substance can be calculated as:

n =W/M, where

W = given mass

M = molar mass

Given chemical reaction is:

2HgO → 2Hg + O₂

From the stoichiometry of the reaction, it is clear that:

2 mole of HgO = produce 1 mole of O₂

Given mass of O₂ = 250 grams

Molar mass of O₂ = 32 g/mole

Mole of produced O₂ = 250g / 32g/mole = 7.81 moles

Now, 7.81 moles of O₂ = produced by 2×7.81 = 15.63 moles of HgO

Hence, option (3) is correct i.e. 15.63 moles is the required moles.

To know more about moles, visit the below link:

brainly.com/question/16060223

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What are the common units for expressing solution concentration?
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