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anyanavicka [17]
3 years ago
13

Mercury(II) oxide (HgO) decomposes to form mercury (Hg) and oxygen (O2). The balanced chemical equation is shown below. 2HgO Rig

ht arrow. 2Hg O2 The molar mass of O2 is 32. 00 g/mol. How many moles of HgO are needed to produce 250. 0 g of O2? 3. 906 moles 7. 813 moles 15. 63 moles 73. 87 moles.
Chemistry
1 answer:
yulyashka [42]3 years ago
3 0

15.63 moles of HgO are needed to produce 250. 0 grams of Oxygen.

<h3>How we calculate moles from masses?</h3>

Moles of any substance can be calculated as:

n =W/M, where

W = given mass

M = molar mass

Given chemical reaction is:

2HgO → 2Hg + O₂

From the stoichiometry of the reaction, it is clear that:

2 mole of HgO = produce 1 mole of O₂

Given mass of O₂ = 250 grams

Molar mass of O₂ = 32 g/mole

Mole of produced O₂ = 250g / 32g/mole = 7.81 moles

Now, 7.81 moles of O₂ = produced by 2×7.81 = 15.63 moles of HgO

Hence, option (3) is correct i.e. 15.63 moles is the required moles.

To know more about moles, visit the below link:

brainly.com/question/16060223

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M1 = 3M M2 = 1.25M V1 = V1=.125L unkown What is V2?
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0.3 L is the final volume when M₁ = 3 M, V₁ = 0.125L, M₂ = 1.25M.

<h3>What is volume?</h3>

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Given data:

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