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zepelin [54]
3 years ago
15

What are the common units for expressing solution concentration?

Chemistry
2 answers:
Ira Lisetskai [31]3 years ago
6 0
It would be mol/dm^3 Formula of concentration: (no. of moles/volume of solution in dm^3) 1 cm^3 = 0.001dm^3 Hope this helped. :)
tamaranim1 [39]3 years ago
3 0
Molarity and molality is widely used as units for expressing concentration. Concentrations can also be show through mass per univ volume. Another example is by parts such as parts per million and parts per billion. Lastly, it can also be expressed through percent by mass or volume.
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Why must energy be used to produce the colors seen
olga_2 [115]

Answer:

Visible light contains all the colors from violet to red. An object gets its color when electrons absorb energy from the light and become “excited” (raised to a state of increased energy). The excited electrons absorb certain wavelengths of light.

The Sun emits light of every possible frequency at once, including at frequencies too high or too low for us to see. But the Sun's highest intensity radiation aligns approximately with our visible range – red through blue. That's no coincidence – like all animals on Earth, we have evolved to make best use of the light available.

Explanation:

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2 years ago
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Use the ideal-gas law to estimate the number of air molecules in your physics lab room, assuming all the air is N2. Assume a roo
stiv31 [10]

Answer:

4.13×10²⁷ molecules of N₂ are in the room

Explanation:

ideal gases Law → P . V = n . R . T

Pressure . volume = moles . Ideal Gases Constant . T° K

T°K = T°C + 273 → 20°C + 273 = 293K

Let's determine the volume of the room:

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We convert the ft³ to L → 5832 ft³ . 28.3L / 1 ft³ = 165045.6 L

1 atm .  165045.6 L = n . 0.082 L.atm/mol.K . 293K

(1 atm .  165045.6 L) / 0.082 L.atm/mol.K . 293K = n

6869.4 moles of N₂ are in the room

If we want to find out the number of molecules we multiply the moles by NA

6869.4 mol . 6.02×10²³ = 4.13×10²⁷ molecules

4 0
3 years ago
A potted plant is placed under a grow lamp, which provides 6,400 J of energy to the plant and the soil over the course of an hou
STatiana [176]

Answer:

823.7g

Explanation:

Using the formula as follows:

Q = m × c × ∆T

Where;

Q = amount of heat (J)

m = mass of substance (g)

c = specific heat capacity (J/g°C)

∆T = change in temperature (°C)

Using the information given in this question as follows:

Q = 6,400 J

m = ?

c of soil = 0.840 J/g°C

∆T = 9.25°C

Using Q = mc∆T

m = Q ÷ c∆T

m = 6,400 ÷ (0.840 × 9.25)

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m = 823.7g

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3 years ago
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Rzqust [24]
An element or compound which occurs naturally in the earth is a mineral
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ELEN [110]

Answer:

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Explanation:

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