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zepelin [54]
3 years ago
15

What are the common units for expressing solution concentration?

Chemistry
2 answers:
Ira Lisetskai [31]3 years ago
6 0
It would be mol/dm^3 Formula of concentration: (no. of moles/volume of solution in dm^3) 1 cm^3 = 0.001dm^3 Hope this helped. :)
tamaranim1 [39]3 years ago
3 0
Molarity and molality is widely used as units for expressing concentration. Concentrations can also be show through mass per univ volume. Another example is by parts such as parts per million and parts per billion. Lastly, it can also be expressed through percent by mass or volume.
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6 0
3 years ago
A solution is made containing 14.6g of CH3OH in 185g H2O.1. Calculate the mole fraction of CH3OH.2. Calculate the mass percent o
Andre45 [30]

Answer:

* x_{CH_3OH}=0.0425

* \%m/m_{CH_3OH}=7.31\%

* m=2.46m

Explanation:

Hello,

In this case, for the mole fraction of methanol we use the formula:

x_{CH_3OH}=\frac{n_{CH_3OH}}{n_{CH_3OH}+n_{water}}

Thus, we compute the moles of both water (molar mass 18 g/mol) and methanol (molar mass 32 g/mol):

n_{CH_3OH}}=14.6g*\frac{1mol}{32g}=0.456molCH_3OH \\\\n_{water}}=185g*\frac{1mol}{18g}=10.3molH_2O

Hence, mole fraction is:

x_{CH_3OH}=\frac{0.456mol}{0.456mol+10.3mol}\\\\x_{CH_3OH}=0.0425

Next, mass percent is:

\%m/m_{CH_3OH}=\frac{m_{CH_3OH}}{m_{CH_3OH}+m_{water}}*100\%\\\\\%m/m_{CH_3OH}=\frac{14.6g}{14.6g+185g}*100\%\\\\\%m/m_{CH_3OH}=7.31\%

And the molality, considering the mass of water in kg (0.185 kg):

m=\frac{n_{CH_3OH}}{m_{water}} =\frac{0.456mol}{0.185kg}\\ \\m=2.46m

Regards.

7 0
3 years ago
The molecular weight of potassium ferricyanide is 329.24 grams/mol. How would you make 1 liter of a 500mM potassium ferricyanide
True [87]

Answer:

w = 164.62 g

Explanation:

molarity of a solution is given as -

Molarity (M)  =  ( w / m ) / V ( in L)

where ,

m = molecular mass ,

w = given mass ,

V = volume of solution ,

From the question ,

M = 500 mM = 0.5 M

( since , 1 mM =  1 / 100 M)

As we know , the molecular mass of potassium ferricyanide = 329.24 g/ mol

V = vol.of solution = 1 L

w = ?

<u>To find the value of w , using the above formula , and putting the respected values , </u>

Molarity (M)  =  ( w / m ) / V ( in L)

0.5  =  ( w / 329.24 ) / 1 L

w = 164.62 g

6 0
3 years ago
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