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Ipatiy [6.2K]
3 years ago
7

Plz help me ... 0.08g + 0.2 < 5 *

Mathematics
2 answers:
Digiron [165]3 years ago
4 0

Answer:

  g < 60

Step-by-step explanation:

Subtract 0.2

  0.08g < 4.8

Divide by 0.08 (the coefficient of g)

  g < 4.8/0.08

  g < 60

Burka [1]3 years ago
3 0
0.08
0.2
+
=
0.28 that’s how u work it out
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27 solid iron spheres,each of radius x cm are melted to form a sphere with radius y cm ,find the ratio of x:y
madam [21]

Radius of 1 solid iron sphere =r

→ Volume =34πr3

→ Volume of 27 solid iron

spheres =27x34πr3

→ 34πr'3=27x34πr3

r'3=2πr3

→r'=3r

(ii) Surface area =4+πr2

SA r'=4πr'2

=4π(3r)2=36πr2

S'S=36πr24πr2=91=1:9

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3 years ago
What would be a line perpendicular to (2,3) (5,5)?
ladessa [460]

9514 1404 393

Answer:

  3x + 2y = 0   or   y = -3/2x

Step-by-step explanation:

The relationship between a line and its perpendicular is that their slopes are opposite reciprocals of each other. So, the thing you need to know about the line through the two given points is its slope. That is found using the slope formula:

  m = (y2 -y1)/(x2 -x1) . . . . . . where the two give points are (x1, y1) and (x2, y2)

Putting your point coordinates in this formula gives ...

  m = (5 -3)/(5 -2) = 2/3

Then the perpendicular line will have a slope that is the opposite reciprocal:

  slope of perpendicular = -1/m = -1/(2/3) = -3/2

You have not said whether the perpendicular line must meet any other requirement, so the simplest one we can write is ...

  y = mx + b . . . . . m is the slope and b is the y-intercept

  y = -3/2x . . . . . . has a y-intercept of 0 (goes through the origin)

Multiplying by 2 and adding 3x gives ...

  3x + 2y = 0 . . . . . standard form equation

_____

<em>Comment on the attachment</em>

The geometry program I used to create the attachment wrote the equation of the line through the given points as ...

 2x -3y = -5 . . . . . standard form equation

The equation of a perpendicular line can be created from this form by swapping the x- and y-coefficients and negating one of them. Simply swapping the coefficients would give ...

  -3x +2y = <something>

In standard form, we want the leading coefficient to be positive, so we can choose to negate the x-coefficient. The <something> can be zero to make the line go through the origin.

  3x +2y = 0 . . . . . a perpendicular in standard form

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If you need to have the line go through a particular point, you can determine the constant value (on the right of the = sign) by putting the point coordinates in for x and y.

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Method summary:

  • find the slope of the given line
  • determine its opposite reciprocal to find the slope of the perpendicular line
  • use that new slope in an appropriate form to have the line go where you want it to go. (Point-Slope Form is often useful)

3 0
2 years ago
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Hoochie [10]

We have to show that this is a square, meaning all the sides are perpendicular and the same distance.  

A(3,4), B(2,-2), C(-4,-1), D(-3,5)

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BC=C-B=(-6, 1).  slope=1/-6=-1/6.   BC²=(-6)²+1²

CD=D-C=(1, 6).   slope=6/1=6    CD²=1²+6²=37

DA=A-D=(6,-1)   slope=-1/6     DA²=37

We see the negative reciprocal slopes, alternating between 6 and -1/6, indicating perpendicular sides.  We see they all have squared distance 37.  Equal perpendicular sides proves its a square.

If we do these problems enough we learn:  There's no point taking the square root.  In fact, there's really no point computing the slopes and the squared distances; we can see it's a square from the pattern of the direction vectors of the sides:  (-1, -6) (-6, 1) (1, 6) (6,-1)

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