The value of W when V = 9 is 405
<h3>How to solve for W?</h3>
The variation is a direct variation from W to V^2.
This means that:
W = kV^2
Where k is the constant of variation.
W = 320 when V = 8 means that:
320 = k * 8^2
Evaluate
320 = 64k
Divide both sides by 64
k = 5
Substitute k = 5 in W = kV^2
W = 5V^2
When V = 9, we have:
W = 5 * 9^2
Evaluate
W = 405
Hence, the value of W when V = 9 is 405
Read more about direct variation at:
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Answer:
16
Step-by-step explanation:
Arrange date in order
3,5,8,12,15,16,20
find median in this case its 12 also khown as 2nd quartile know find the themedian of data that is on the right right of median or 2nd Quartiles That will be the 3rd quartile...
Step-by-step explanation:
they are both linear functions. A function is linear when the degree on X is equal to 1
It must be a and c, as these are the only two with four closed sides
