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grigory [225]
2 years ago
11

Solve the proportion below.

Mathematics
2 answers:
melamori03 [73]2 years ago
8 0
Cross multiply

19(x) = 30(9.5)

Simplify

19x = 285

Divide 19 from both sides

19x/19 = 285/19

x = 285/19

x = 15

B. 15 is your answer

hope this helps
skelet666 [1.2K]2 years ago
8 0

19x = 30 * 9.5

x    = 30 * 9.5 / 19

=  30 /2

= 15 answer
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Check the picture below.

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3 years ago
The coach pays $72 for 18 hamburgers. What is the cost per hamburger? What math concept do you use to solve the problem?
Talja [164]

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Step-by-step explanation:

you divide 72 by 18.

5 0
3 years ago
Read 2 more answers
Need help with this please
FromTheMoon [43]

Answer: -2

Step-by-step explanation:

Slope=rise/run

In this case we rise up 4

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3 years ago
Find the area of the circle.
juin [17]

Answer:

See Explanation Below

Step-by-step explanation:

Your question isn't clear; However, I'll solve in two ways

1. Diameter = 14 cm

2. Radius = 14 cm

<em></em>

<em>When Diameter = 14 cm</em>

Given

Area = \pi r^2

Diameter = 14cm

Required

Calculate the area of the circle

First, the radius has to be solved;

Radius = \frac{1}{2} Diameter

Radius = \frac{1}{2} * 14cm

Radius = 7cm

Using the given formula;

The area is as follows

Area = \pi r^2

Area = 3.14 * 7^2

Area = 3.14 * 49

Area = 153.86cm^2

<em>When Radius = 14 cm</em>

Given

Area = \pi r^2

Radius = 14cm

Required

Calculate the area of the circle

Using the given formula;

The area is as follows

Area = \pi r^2

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7 0
3 years ago
Find the volume of a trough 5 meters long whose ends are equilateral triangles, each of whose
yawa3891 [41]

Answer:

V=5\sqrt{3}\ m^3

Step-by-step explanation:

we know that

The volume of a trough is equal to

V=BL

where

B is the area of equilateral triangle

L is the length of a trough

step 1

Find the area of  equilateral triangle B

The area of a equilateral triangle applying the law of sines is equal to

B=\frac{1}{2} b^{2} sin(60\°)

where

b=2\ m

sin(60\°)=\frac{\sqrt{3}}{2}

substitute

B=\frac{1}{2}(2)^{2} (\frac{\sqrt{3}}{2})

B=\sqrt{3}\ m^{2}

step 2

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V=BL

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B=\sqrt{3}\ m^{2}

L=5\ m

substitute

V=(\sqrt{3})(5)

V=5\sqrt{3}\ m^3

3 0
3 years ago
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