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soldi70 [24.7K]
3 years ago
11

What is the value of b in ax - by = -5

Mathematics
1 answer:
m_a_m_a [10]3 years ago
5 0

Answer:

D,

Step-by-step explanation:

the is the value of b in ax -by =-5

D , cant isolate b

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Find x. <br> Side splitter theorem
professor190 [17]

Answer:

x = 9

Step-by-step explanation:

The outer and inner triangles are similar, thus the ratios of corresponding sides are equal, that is

\frac{8}{8+4} = \frac{x-3}{x} , that is

\frac{8}{12} = \frac{x-3}{x} ( cross- multiply )

12(x - 3) = 8x

12x - 36 = 8x ( subtract 8x from both sides )

4x - 36 = 0 ( add 36 to both sides )

4x = 36 ( divide both sides by 4 )

x = 9

3 0
3 years ago
Solve.<br> 4 x + 6 &lt; − 6<br><br> Thankyou In advance :&gt;
andrew-mc [135]

Answer:

x < -3

Step-by-step explanation:

Step 1: Subtract 6 from both sides.

  • 4x + 6 - 6 < -6 - 6
  • 4x < -12

Step 2: Divide both sides by 4.

  • \frac{4x}{4} < \frac{-12}{4}
  • x < -3

Therefore, the answer is x < -3.

6 0
3 years ago
A quality analyst of a tennis racquet manufacturing plant investigates if the length of a junior's tennis racquet conforms to th
Burka [1]

Answer:

Confidence interval : 21.506 to 24.493

Step-by-step explanation:

A quality analyst selects twenty racquets and obtains the following lengths:

21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

So, sample size = n =20

Now we are supposed to find Construct a 99.9% confidence interval for the mean length of all the junior's tennis racquets manufactured at this plant.

Since n < 30

So we will use t-distribution

Confidence level = 99.9%

Significance level = α = 0.001

Now calculate the sample mean

X=21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

Sample mean = \bar{x}=\frac{\sum x}{n}

Sample mean = \bar{x}=\frac{21+25+23+22+24+21+25+21+23+ 26+ 21+24+22+ 24+23+21+ 21+ 26+23+ 24}{20}

Sample mean = \bar{x}=23

Sample standard deviation = \sqrt{\frac{\sum(x-\bar{x})^2}{n-1}}

Sample standard deviation = \sqrt{\frac{(21-23)^2+(25-23)^2+(23-23)^2+(22-23)^2+(24-23)^2+(21-23)^2+(25-23)^2+(21-23)^2+(23-23)^2+(26-23)^2+(21-23)^2+(24-23)^2+(22-23)^2+(24-23)^2+(23-23)^2+(21-23)^2+(21-23)^2+(26-23)^2+(23-23)^2+(24-23)^2}{20-1}}

Sample standard deviation= s = 1.72

Degree of freedom = n-1 = 20-1 -19

Critical value of t using the t-distribution table t_{\frac{\alpha}{2} = 3.883

Formula of confidence interval : \bar{x} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}}

Substitute the values in the formula

Confidence interval : 23 \pm 1.73 \times \frac{1.72}{\sqrt{20}}

Confidence interval : 23 -3.883 \times \frac{1.72}{\sqrt{20}} to 23 + 3.883 \times \frac{1.72}{\sqrt{20}}

Confidence interval : 21.506 to 24.493

Hence Confidence interval : 21.506 to 24.493

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3 years ago
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Answer:

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Step-by-step explanation:

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Manu tickets should $68 for 12

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